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3 years ago

What’s is a angle defined

Mathematics

1 answer:

Mashutka [201]3 years ago

7 0

Answer:

the space (usually measured in degrees) between two intersecting lines or surfaces at or close to the point where they meet.

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Margaret [11]

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2 years ago

Complete the following statement. If AB = BC and A,B,C are collinear, then b is the BLANK of AC

algol13

Answer:

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Step-by-step explanation:

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3 years ago

Question 2 (essay worth 10 points)

Sliva [168]

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is {JPR, JRP, PJR, PRJ, RJP, RPJ}.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

Minni is arranging 3 different music CDs in a row on a shelf.

Three CDs are a jazz cd (j), a pop cd (p), and a rock cd (r).

The sample space means all the possible ways to arrange the CDs.

Total arramgement = 3! = 3×2×1 = 6

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is:

{JPR, JRP, PJR, PRJ, RJP, RPJ}

Thus, the sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is {JPR, JRP, PJR, PRJ, RJP, RPJ}.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

4 0

2 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

= 0.9821 - .2420

= 0.7401

3 0

3 years ago

Help me pleaseeee<br><br><br><br><br> ....

Alex17521 [72]

Answer:

Step-by-step explanation:

8 0

3 years ago