On reading at An artic research station showed that the temperature was -35 C. What is this temperature in degrees Fahrenheit?

Help me pls , will give brainliest

shusha [124]

Answer:

m/2 = 87°

m/4 = 87°

m/7 = 93°

Have a good day, please! :)

5 0

2 years ago

I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE

makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

${a}^{2} + {b}^{2} = {c}^{2}$

First Mistake : Line 2

$a = x \\ b = 6 \\ c = 10$

Second Mistake : Line 4

$136 = {x}^{2} \\ not \\ 136 = x$

Correct Solution :

${x}^{2} + {6}^{2} = {10}^{2} \\ {x}^{2} = {10}^{2} - {6}^{2} \\ {x}^{2} = 100 - 36 \\$

${x}^{2} = 64 \\ \sqrt{ {x}^{2} } = \sqrt{64} \\ x = 6$

3 0

3 years ago

How do I find the missing value

liberstina [14]

Okay. Since the "y" value and 82* are on the same straight line, their values will always add up to make a sum of 180. So if you subtract 82 from 180 you get 98*. So your "y" value is equal to 98*.

Now, all of the degree values added together should give you a sum of 360, so now we must add the values we know, in order to find the "x" value. So, 112*+82*+98*=292. Now we know that the difference of 360 and 292 will give us the x value. So finally, 360-292=68. So your "x" value is equal to 68.

y=98
x=68

6 0

4 years ago

Joe is straight into running a half marathon in too much this week he ran 1,200,000 km on Monday 2400 m on Wednesday and 4.6 km

lara31 [8.8K]

Answer:

1202404.6

Step-by-step explanation:

1,200,000 + 2400 =1202400

1202400 + 4.6 = 1202404.6

6 0

3 years ago

The mean of the heights of three buildings A,B and C is 14.2m. The mean of the heights of five buildings A,B,C, D and E is 14.8m

Jobisdone [24]

<h3>Answer: 15.7 meters</h3>

========================================================

Work Shown:

s = sum of the heights of buildings A,B,C

s/3 = mean of the heights of buildings A,B,C

s/3 = 14.2

s = 3*14.2

s = 42.6

The buildings A,B,C have their heights add up to 42.6

--------------

r = sum of the heights of buildings A,B,C,D,E

r/5 = mean of the heights of buildings A,B,C,D,E

r/5 = 14.8

r = 5*14.8

r = 74

--------------

r-s = (sum of heights of A,B,C,D,E)-(sum of heights of A,B,C)

r-s = sum of the heights of buildings D and E

r-s = 74-42.6

r-s = 31.4

(r-s)/2 = mean height of buildings D and E

(r-s)/2 = 31.4/2

(r-s)/2 = 15.7 meters is the average height of buildings D and E.

4 0

3 years ago