2. The center of a circle is at (4,-5). The radius of the circle is 10 units. Write the equation of the

Answer ASAP please!

Rom4ik [11]

Answer:

e. is incorrect

sin (x)= f/e

3 0

2 years ago

Determine the range for the function y = (x - 3 )^2 + 4.

Aleksandr [31]

Answer:

<h3>Solutions are x=2 and x=−2 . At these points the function has vertical asymptotes. To address the range, let's first transform...</h3>

7 0

2 years ago

You have constructed wooden forms for pilings. The pilings are in the shape of rectangular solids, each measuring 10 ft. high an

Anna [14]

Volume V=3*10=30 feet³ -- > one <span>piling

10 </span>pilings----------------- > V=30*10=300 feet³

The answer is 300 feet³ of cement

3 0

3 years ago

Read 2 more answers

It takes Peter 4 hours to walk 12 miles.If he continues to walk at the same rate, how long will it take him to walk:

blondinia [14]

Answer:

a]2.3 hrs

b]3.6hrs

Step-by-step explanation:

4hrs = 12 miles

x = 7miles

4 x 7=28/12=2.3

4 x 11=44/12=3.6hrs

6 0

3 years ago

Read 2 more answers

Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for

KIM [24]

Answer:

a) The recurrence formula is $P_n = \frac{109}{100}P_{n-1}$ .

b) The general formula for the population of Tacoma is

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write $P_0 = 200 000$ . For the population in 2001 we will use $P_1$ , for the population in 2002 we will use $P_2$ , and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that $P_0$ is equal to $P_1$ plus 9% of the population of 2000. Notice that this can be written as

$P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0$ .

In 2002, we will have the population of 2001, $P_1$ , plus the 9% of $P_1$ . This is

$P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1$ .

So, it is not difficult to notice that the general recurrence is

$P_n = \frac{109}{100}P_{n-1}$ .

b) In the previous formula we only need to substitute the expression for $P_{n-1}$ :

$P_{n-1} = \frac{109}{100}P_{n-2}$ .

Then,

$P_n = \left(\frac{109}{100}\right)^2P_{n-2}$ .

Repeating the procedure for $P_{n-3}$ we get

$P_n = \left(\frac{109}{100}\right)^3P_{n-3}$ .

But we can do the same operation n times, so

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) Recall the notation we have used:

$P_{0}$ for 2000, $P_{1}$ for 2001, $P_{2}$ for 2002, and so on. Then, 2016 is $P_{16}$ . So, in order to obtain the approximate population of Tacoma in 2016 is