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AfilCa [17]
3 years ago
15

Find the equation of the line that is perpendicular to y=1/3x-3 and passes through the point (3,-2)

Mathematics
1 answer:
sveta [45]3 years ago
5 0

Answer:

y = -3x + 7

Step-by-step explanation:

Using the equation of line

y = mx + C

y - y_1 = m(x - x_1)

First find the slope

With eqn y = 1/3x - 3

Note, if two lines are perpendicular, their slope will be negative reciprocal

slope = m = -3/1

Using y - y_1 = m(x - x_1)

With point ( 3, -2)

x_1 = 3

y_1 = -2

y - (-2) = -3/1(x - 3)

y + 2 = -3/1(x -3)

Open bracket

y + 2 = -3(x - 3)/1

y + 2 = (-3x +9)/1

y = (-3x + 9 )/1 - 2

LCM is 1

y = -3x + 9 - 2

y = -3x + 7

The equation of the line is

y = -3x + 7

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Given right triangle A w/a hypotenuse length of 3y + x and a leg of y-x, and right triangle B, w/ a hypotense length of y+5 and
SpyIntel [72]
Triangle A

hypotenuse: 3y + x
leg: y - x

Triangle B

hypotenuse: y + 5
leg: x + 5

Congruency => 3y + x = y + 5 and y - x = x + 5

Solve the system

3y + x = y + 5 -> 2y + x = 5
y - x = x + 5 -> y - 2x = 5

  2y + x = 5
-2y + 4x = -10

5x = -5
x = -1
y = (5 -(-1)) / 2 = 6/2 = 3

Verify:

 hypotenuses
3y + x = 9 - 1 = 8
y + 5 = 3 + 5 = 8

Legs:

y - x = 3 -(-1) = 3 + 1 = 4
x + 5 = -1 + 5 = 4.

Then both hypotenuses and both legs are congruent.

Answer: x = -1 and y = 3


4 0
3 years ago
Please explain how to solve this step by step.
Phantasy [73]

Answer:

  (a^8)/(b^9)

Step-by-step explanation:

Two rules of exponents come into play.

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

__

Applying the first rule, we have ...

  (a^3)/(a^-5) × (b^-2)/(b^7) = a^(3 -(-5)) × b^(-2 -7) = a^8 × b^-9

Applying the second rule gives the simplified form ...

  = (a^8)/(b^9)

5 0
2 years ago
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
suppose you have $11000 to invest. which of the two rates would yield the larger amount in 5 years: 6% compounded monthly or 5.8
umka21 [38]

Answer:

  6% monthly

Step-by-step explanation:

The monthly rate being compounded when the interest is 6% per year is ...

  6%/12 = 0.5%

so the multiplier each month is

  1 + 0.5% = 1.005

___

The monthly multiplier when 5.86% is compounded continuously is ...

  e^(5.86%/12) ≈ 1.004895

The 6% rate will give a larger yield after any length of time.

6 0
3 years ago
After graphing 4x-2y=5 and y=x, in how many points do they intersect
Angelina_Jolie [31]

Answer:

1 at (2.5, 2.5)

Step-by-step explanation:

you can try graphing it on desmo

3 0
4 years ago
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