4 years ago

How would i solve this?

Mathematics

1 answer:

Flauer [41]4 years ago

4 0

Answer: C

Step-by-step explanation:

The enequality includes x values equal to or greater than -2 and less than(but not equal to) 1.

so the possible integers would be -2 -1 0.

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given that g(×)=<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20-%203%7D%7Bx%20%20%2B%204%7D%20" id="TexFormula1" title=" \fr

valkas [14]

ANSWER:

$\begin{gathered} a)\text{ 6} \\ b)\text{ 0} \\ c)\text{ inderminate} \\ d)\text{ 1.6} \\ e)\text{ }\frac{x+h-3}{x+h+4} \end{gathered}$

STEP-BY-STEP EXPLANATION:

We have the following function

$g(x)=\frac{x-3}{x+4}$

Now, we calculate for each case the result of the function.

a) g(6)

$g(6)=\frac{6-3}{6+4}=\frac{3}{10}$

b) g(3)

$g(3)=\frac{3-3}{3+4}=\frac{0}{7}=0$

c) g(-4)

$g(-4)=\frac{-4-3}{-4+4}=-\frac{7}{0}=\text{ inderminate}$

d) g(-15.75)

$g(-15.75)=\frac{-15.75-3}{-15.75+4}=\frac{-18.78}{-11.75}=1.59\cong1.6$

e) g(x+h)

$g(x+h)=\frac{x+h-3}{x+h+4}$

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