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3 years ago

Which number line best shows how to solve −8 − (−6)?

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

Answer:

A number line from negative 10 to 10 is shown with numbers labeled at intervals of 2. An arrow is shown from point 0 to negative 8. Another arrow points from negative 8 to negative 2.

Step-by-step explanation:

find the number line best shows how to solve −8 − (−6)

In the number line first we start with -8 . negative and negative becomes positive

from -8 move 6 units to the right. So it ends at -2

A number line from negative 10 to 10 is shown with numbers labeled at intervals of 2. An arrow is shown from point 0 to negative 8. Another arrow points from negative 8 to negative 2.

Llana [10]3 years ago

6 0

Answer:

-8

Step-by-step explanation:

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What is the solution to the equation 2/3x+1=1/6x-7?

Alborosie

As it is, in accordance with the priorities of the operators (or the PEMDAS rule) the equation without parentheses mean
(2/3)x+1=(1/6)x-7
I do not suppose you mean the above, since the solution is relatively trivial.

I suppose you actually mean
2/(3x+1)=1/(6x-7)
in which case you would cross-multiply:
2(6x-7)=(3x-1)
and expand/distribute
12x-14=3x-1
isolate x and solve
12x-3x=-1+14
9x=13
x=13/9
If you mean the first form of equation without parentheses, my apologies.

5 0

3 years ago

Delia measured her bathtub to be 2 meters long. What is an equivalent measurement?

allochka39001 [22]

An equivalent measurement to 2 meters is 200 cm. Since 1 meter is equivalent to 100 cm, multiply both of them by two. So, your answer is - 2 meters is equivalent to 200 cm.

Hope it helps :)

4 0

3 years ago

Apply the rule (-x, y - 2) to the following point, what is the result?

BaLLatris [955]

Answer: Second Choice. (3, 3)

Step-by-step explanation:

Given point

(x, y) = (-3, 5)

Given the rule for application

(-x, y - 2)

Determine the new x-value

x = -3

-x = - (-3) = 3

Determine the new y-value

y = 5

y - 2 = (5) - 2 = 3

Therefore, the result is $\Large\boxed{(3,~3)}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

2 years ago

Read 2 more answers

Translate this phrase into an algebraic expression.

Verizon [17]

Answer:

Step-by-step explanation:

9n-2

5 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago