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3 years ago

A regular pentagon has side lengths of 14.1 centimeters and an apothem with length 12 centimeters.

Mathematics

2 answers:

lina2011 [118]3 years ago

8 0

Answer:

The approximate area of the regular pentagon is 423 sq.cm.

Step-by-step explanation:

Formula of area of regular pentagon = $\frac{Pa}{2}$

P=Perimeter of pentagon

a=Apothem

Side of pentagon = 14.1 cm

Perimeter of pentagon = $5 \times Side = 5 \times 14.1=70.5$

Apothem=12 cm

Area of regular pentagon = $\frac{70.5 \times 12}{2}=423 cm^2$

Hence the approximate area of the regular pentagon is 423 sq.cm.

Irina18 [472]3 years ago

3 0

Answer:

The answer is C on Edge 2020

Step-by-step explanation:

I did the Exam

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What is 1/5 divided by 5/7

vampirchik [111]

1/5 divided by 5/7 is 7/25
1/5 ÷ 7/5 = 7/25

Your answer is 7/25

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3 years ago

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

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2 years ago

Select the equivalent expression. <br><br> A, B or C?

Alina [70]

Answer:

Step-by-step explanation:

The relevant rules of exponents are ...

(a^b)^c = a^(bc)

a^-b = 1/a^b

$\left(\dfrac{2^{-10}}{4^2}\right)^7=\dfrac{2^{(-10)(7)}}{4^{(2)(7)}}=\dfrac{2^{-70}}{4^{14}}\\\\=\boxed{\dfrac{1}{2^{70}\cdot 4^{14}}}$