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3 years ago

A regular pentagon has side lengths of 14.1 centimeters and an apothem with length 12 centimeters.

Mathematics

2 answers:

lina2011 [118]3 years ago

8 0

Answer:

The approximate area of the regular pentagon is 423 sq.cm.

Step-by-step explanation:

Formula of area of regular pentagon = $\frac{Pa}{2}$

P=Perimeter of pentagon

a=Apothem

Side of pentagon = 14.1 cm

Perimeter of pentagon = $5 \times Side = 5 \times 14.1=70.5$

Apothem=12 cm

Area of regular pentagon = $\frac{70.5 \times 12}{2}=423 cm^2$

Hence the approximate area of the regular pentagon is 423 sq.cm.

Irina18 [472]3 years ago

3 0

Answer:

The answer is C on Edge 2020

Step-by-step explanation:

I did the Exam

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3 years ago

Edg vector operations, any help appreciated!

viktelen [127]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c$

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$\large \tt Solution \: :$

Vector d can be represented as :

$\qquad \tt \rightarrow \: - 2 \hat i - 2 \hat j$

Vector c can be represented as :

$\qquad \tt \rightarrow \: 4 \hat i + 4\hat j$

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

$\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) = - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = - ( 4 \hat i + 4 \hat j) - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = (- 4 \hat i - 2 \hat i) + ( - 4 \hat j - 2 \hat j)$

$\qquad \tt \rightarrow \: x = - 6 \hat i -6 \hat j$

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago

What are RQS and TQS?

yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

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3 years ago

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marin [14]

Answer:

Step-by-step explanation:

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3 years ago