Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.
Algebraically, that will be expressed as:
Answer:
c.63
will be your answer
Step-by-step explanation:
Answer:
The answer is Tonya's phone had the greater initial trade-in value.
Leo's phone decreases at an average rate slower than the trade in value of Tonya's phone.
Step-by-step explanation:
Given
Tonya

Leo




Solving (a): The phone with greater initial value
The initial value is when x = 0. So, we have:




From Leo's table

By comparison;

i.e.

<em>So: Tonya's had the greater initial trade-in value</em>
Solving (b): The phone with lesser rate
An exponential function is:

Where:

For Tonya

For Leo, we have:


So, the equation becomes:

and 
Solving
, we have:



becomes

Divide both sides by 480

Take square roots

-- Leo's rate
By comparison; Leo's rate is slower i.e. 0.87 < 0.88