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dolphi86 [110]
3 years ago
14

The answer is 5/3, but I don’t know the solution.

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Check the picture below.

let's bear in mind that the segment MN is simply the sum of MQ + QN, and since M and N are midpoints, they cut that respective section into two equal halves.

\bf \begin{cases} PQ=5QR\\ MN = \frac{PQ}{2}+\frac{QR}{2} \end{cases}\qquad \qquad \cfrac{PQ}{MN}\implies \cfrac{5QR}{\frac{PQ}{2}+\frac{QR}{2}}\implies \cfrac{5QR}{\frac{PQ+QR}{2}} \\\\\\ \cfrac{\frac{5QR}{1}}{\frac{PQ+QR}{2}}\implies \cfrac{5QR}{1}\cdot \cfrac{2}{PQ+QR}\implies \cfrac{10QR}{\underline{PQ}+QR}\implies \cfrac{10QR}{\underline{5QR}+QR}

\bf \cfrac{~~\begin{matrix} 10QR \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 6QR \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{5}{3}

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Answer:

162.4 in²

Step-by-step explanation:

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Let's start with what we know:

Area of regular octagon = 1/2 x perimeter x apothem

We know the apothem, so all that we need to find to fill in the above equation is the perimeter:

perimeter = 8 x 5.8 = 46.4in

Now we can fill in our original equation and solve:

Area of regular octagon = 1/2 x perimeter x apothem

Formula = n (s/2)² divided by tan( π /n)

   = 8 (5.8/2)²  divided by tan ( π /8)

                 = 162.4283 in²

ORRR when rounded to the nearest tenth,

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6 0
3 years ago
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Answer:

1.54 in²

Step-by-step explanation:

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8 0
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The figure shown is a kite. What is the x-coordinate of point P?
tresset_1 [31]

The answer to the above question can be determined as -

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6 0
3 years ago
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dolphi86 [110]

Answer:

c. Multiple zero is 3; multiplicity is 2

Step-by-step explanation:

The factor is repeated, that is, the factor  ( x  −  3 )  appears twice. The number of times a given factor appears in the factored form of the equation of a polynomial is called the multiplicity. The zero associated with this factor,  x  =  3 , has multiplicity 2 because the factor  ( x  −  3 )  occurs twice.

Then

Multiple zero is 3; multiplicity is 2.

6 0
2 years ago
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