Answer:
4
Step-by-step explanation:
to solve | a | - | b | + | c | we need to plug in the given values
a = -8
b = -5
c = 1
the | | bars mean absolute value which is the exact value a number is away from 0 on a number line. an absolute value has to be positive, not a negative, as you cant be negative spaces away from something. plugging in the values into the equation we have:
| -8 | - | -5 | + | 1 |
the absolute value of -8 is 8, as -8 is 8 units away from 0 on a number line
like wise with -5, the absolute value of -5 is 5, as -5 is 5 units away from 0 on a number line
1 is the absolute value of 1 as its 1 unit away from 0 on a number line
the new expression looks like the following:
8 - 5 + 1
now we just add/subtract
8 -5 = 3
3 + 1 = 4
the solution to this expression is 4
Answer:
c) 255
Step-by-step explanation:
d isn't divisible by 5 and both a and b aren't divisible by 3
You need to construct at least 2 angle bisectors to help locate the incircle's center (aka the "incenter"). The incircle is the largest circle possible that is inside the triangle, that doesn't overflow or spill outside of the triangle. An angle bisector cuts an angle in half.
Answer:
8/15
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
Tan = Opposite/Adjacent
The side opposite angle B is side AC. The side adjacent to angle B is side BC. So, the tangent of angle B is ...
tan(B) = AC/BC = 8/15
Answer:
Domain is all real numbers
Range is

Step-by-step explanation:
The given function is

This is a maximum quadratic function therefore the domain is all real numbers.
Let us complete the square to find the vertex.




Therefore the range is


See graph