Answer:
Step-by-step explanation:
Given the following :
- - - Jhs
Basic level - - - - Boys - - - - Girls - - - - Total
Primary - - - - - - - 49 - - - - - - 51 - - - - - - 100%
Jhs - - - - - - - - - - 56 - - - - - - 44. - - - - - - 100%
With the information above,
Primary Dropout percentage:
BOYS : [49 / (49 +51)] × 100.= 49%
GIRLS : [51 / (49 +51)] × 100.= 51%
Jhs: Dropout percentage
BOYS : [56 / ( 56 + 44) × 100 = 56%
GIRLS : [44 / (44 +56)] × 100.= 44%
The equation should look something like:
x+16 = 32
or
16+x = 32
Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:

Hence, the constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
We use

Now we have

Hope that useful for you
Answer:
1 decilitre
Step-by-step explanation:
You can look up charts for these. Look up litre chart