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VladimirAG [237]
3 years ago
9

Margaret’s bottle of shampoo is 7/8 full. She uses 1/3 of the shampoo in the bottle to wash the dog. Estimate what fraction of s

hampoo is left. Use whole numbers and benchmark fractions to explain.
Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

Fraction of shampoo left = \frac{13}{24}

Solution:

Given fraction of full shampoo  =\frac{7}{8}.

Fraction of shampoo Margaret used  =\frac{1}{3}

Fraction of shampoo left = Full shampoo – fraction of shampoo used

                                          =\frac{7}{8}-\frac{1}{3}

To make the denominators same do cross multiplication.

                                          =\frac{7\times3}{8\times3}-\frac{1\times8}{3\times8}

                                          =\frac{21}{24}-\frac{8}{24}

                                          =\frac{21-8}{24}

                                          =\frac{13}{24}

Hence \frac{13}{24} of the shampoo bottle is left.

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Interpret the following table about school dropout at the basic level (5 marks)
barxatty [35]

Answer:

Step-by-step explanation:

Given the following :

- - - Jhs

Basic level - - - - Boys - - - - Girls - - - - Total

Primary - - - - - - - 49 - - - - - - 51 - - - - - - 100%

Jhs - - - - - - - - - - 56 - - - - - - 44. - - - - - - 100%

With the information above,

Primary Dropout percentage:

BOYS : [49 / (49 +51)] × 100.= 49%

GIRLS : [51 / (49 +51)] × 100.= 51%

Jhs: Dropout percentage

BOYS : [56 / ( 56 + 44) × 100 = 56%

GIRLS : [44 / (44 +56)] × 100.= 44%

8 0
3 years ago
Nancy had 16 chocolate candies in a bag. Her mother put a handful of candies in the bag. When Nancy counts her chocolate candies
ryzh [129]

The equation should look something like:


x+16 = 32


or



16+x = 32

5 0
3 years ago
Read 2 more answers
A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ
Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = 2.2\times 7.4=16.28

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = 2.2\times -6.2=-13.64

Thus change in moment is: 16.28-(-13.64)=29.92

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

\frac{29.92}{0.25}=119.68

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0
3 years ago
Factor *<br> (x^2/9)- 64
Hoochie [10]

Step-by-step explanation:

We use

a ^{2}  -  \times ^{2}  = (a -  \times )(a +  \times )

Now we have

\frac{ { \times }^{2} }{9}  - 64 = ( \frac{ \times }{3} ) ^{2}  -  {8}^{2}  \\  = ( \frac{ \times }{3}  - 8)( \frac{ \times }{3}  + 8)

Hope that useful for you

5 0
3 years ago
Kelly had one liter of soda she divided equally into 10 classes to share with her friends how much total did each friend get.: 1
xxMikexx [17]

Answer:

1 decilitre  

Step-by-step explanation:

You can look up charts for these. Look up litre chart

7 0
2 years ago
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