Answer:
Its a long answer.........
Let makes the table neater. event D= 100m, even E=800m
(Event D) (Event E)
A won the race (Event A) 30 50
B won the race (Event B) 60 25
A and B tied (Event T) 10 25
B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win in both race.
Chance of B did not win 100-m= 30+10/10=40%
Chance of B did not win 800-m= 50+25/10=75%
The difference would be 75%-40%=35% more likely to lose 800-m race
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1. What percentage of all the races are ties?
IfThe chance for the race become tie is 10% for 100m and 25% for 800m. Assuming that the 200 race is divided equally, then there would be 100 race of 100-m and 100 race of 800-m.
The number of the event of ties would be:
(100*10% + 100*25%)/ 200= 35/200= 17.5%
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2. If someone wins the race today, is it more likely for A to win or B to win? How much more likely?The event should be independent because the two events should not influence each other. That means the probability will not change and no one becomes more likely to win the next race.
Credits: Brainly and Sisters math notebook(cuz to cross check);)
