3 years ago

What is the equation of the line that passes through the point (-4, -8) and haves a slope of 4

Mathematics

1 answer:

irinina [24]3 years ago

5 0

Answer:

y=4x+8

Step-by-step explanation:

y-y1=m(x-x1)

y-(-8)=4(x-(-4))

y+8=4(x+4)

y=4x+16-8

y=4x+8

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2 years ago

5(2x)to the third power

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(5(2x))^3
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3 years ago

Can someone help me please ???????

Inessa [10]

Answer:

d=1

Step-by-step explanation:

Factor d^2 - 2d - 8 into (d-4)(d+2)

Move -2/d+2 onto the other side, changing it into 2/d+2.

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4}+\frac{2}{d+2} = 0$

Let the empty side equal zero.

Add 3/d-4 and 2/d+2

$\frac{5d-2}{(d+2)(d-4)}$

Then add that to -3d.

$\frac{2d-2}{(d+2)(d+4)}$

Multiply 0 by d+2 and d-4 to get 2d-2 by itself.

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I can't edit the equation, but it's d-4 althroughout the question. Sorry for being so slow.

6 0

3 years ago

How is this no solution? 9x+8y=15 9x+8y=30. Please show your work.

Brilliant_brown [7]

9x+8y=15
9x+8y=30

There can't be a solution because 9x+8y equal different things in both.

Hope this helps :)

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3 years ago

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