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LenKa [72]
3 years ago
14

If 1/2 gallon of paint covers 1/12 of a wall then how much paint is needed for the entire wall

Mathematics
1 answer:
netineya [11]3 years ago
5 0

1/2 gallon of paint covers 1/12 of a wall , 12 times as much paint will cover 12 times the area you can solve this by 12*1/2=6.

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The area of a rectangle is 21 cm². If one side exceeds the other by 4 cm, find the dimensions of the rectangle.​
Over [174]

Answer:

3cm and 7cm

Step-by-step explanation:

The length is 7cm.

The width is 3cm.

Area = Length × Width = 7cm × 3cm = 21cm²

7 0
3 years ago
How do you solve this triangle by using the law of sine where
mars1129 [50]
Actually, when you know 2 sides and an included angle, you use the Law of Cosines. (and we don't know if theta is an included angle).
Solving for side c
c^2 = a^2 + b^2 -2ab * cos(C)
c^2 = 36 + 16 - 2*6*4 * cos(60)
c^2 = 52 -48*.5
c^2 = 28
c = 5.2915

Using the Law of Sines
side c / sin(C) = side b / sin (B)
5.2915 / sin(60) = 4 / sin (B)
sin(B) = sin(60) * 4 / 5.2915
sin(B) = 0.86603 * 4 / 5.2915
<span><span>sin(B) = 3.46412 </span> / 5.2915
</span> <span><span><span>sin(B) = 0.6546571451 </span> </span> </span> 
Angle B = 40.894 Degrees

sin (A) / side a = sin (B) / side b
sin (A) = 6 * sin (40.894) / 4
sin (A) = 6 * 0.65466 / 4
sin (A) = .98199
angle A = 79.109 Degrees

angle C = 60 Degrees


7 0
4 years ago
What would be the midpoint of a line segment with endpoints at (0,1)<br> and <br>(5,7) ?​
liubo4ka [24]

Answer:

(2.5, 4 )

Step-by-step explanation:

Using the midpoint formula

Given endpoints (x₁, y₁ ) and (x₂, y₂ ), then midpoint is

[0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Given

(0, 1) and (5, 7), then

midpoint = [ 0.5(0 + 5), 0.5(1 + 7) ] = (0.5(5), 0.5(8)) = (2.5, 4)

5 0
3 years ago
Calculate the product using partial products.
GrogVix [38]
7,680
To my knowledge, but if someone else answers, maybe trust them
3 0
3 years ago
An aquarium tank can hold 7200 liters of water. there are two pipes that can be used to fill the tank. the first pipe alone can
Arada [10]

The first pipe pumps out

\dfrac{7200\text{ L}}{48\text{ min}}=\dfrac{150\text{ L}}{1\text{ min}}

while the second pipe pumps out

\dfrac{7200\text{ L}}{96\text{ min}}=\dfrac{75\text{ L}}{1\text{ min}}

So together, both pipes pump out

\dfrac{150+75\text{ L}}{1\text{ min}}=\dfrac{225\text{ L}}{1\text{ min}}=\dfrac{7200\text{ L}}{32\text{ min}}

That is, with both pipes filling the tank, it should take 32 minutes total.

4 0
3 years ago
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