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Nadusha1986 [10]
3 years ago
9

What percent of a meter is 30 cm

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0
A meter = 10000 cm

30cm/1m
30/10000
=0.003
x100 (for the percent)

=0.3%

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Find x if the average of 20,20,19,13 and x is 16
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16 times the quantity of numbers, in this case 5, which = 80, then subtract each number, 80-20-20-19-13=8.  X should = 8
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Please help me out!​
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Answer:

B is correct because it value become 15^9

Step-by-step explanation:

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I craft store retailer uses a markup rate of 65%. A scrapbook kit cost three retailer $20 I did. What is the selling price of th
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Answer

Find out the  selling price of the scrapbook kit .

To prove

As given

I craft store retailer uses a markup rate of 65%.

A scrapbook kit cost $20 .

Than 65% is written in the decimal form.

= \frac{65}{100}

= 0.65

Mark up price = 0.65 × 20

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Selling price of Scrapbook kit = Cost of Scrapbook kit + Mark up price.

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Therefore the  the selling price of the scrapbook kit $33.

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47.93 to the nearest tenth
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47.90 is your answer to the nearest tenths
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<img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Csum_%7Bn%20%3D%201%7D%5E%7B%20%5Cinfty%20%7D%20%20%7B4%7D%5E%7B%20-%20
r-ruslan [8.4K]

Answer:

\dfrac{1}{3}

Step-by-step explanation:

<u>Given</u>:

\displaystyle \sum^{\infty}_{n=1} 4^{-n}

The <u>sigma notation</u> means to find the sum of the given <u>geometric series</u> where the first term is when n = 1 and the last term is when n = ∞.

To find the <u>first term</u> in the series, substitute n = 1 into the expression:

\implies a_1=4^{-1}=\dfrac{1}{4}

The <u>common ratio</u> of the geometric series can be found by dividing one term by the previous term:

\implies r=\dfrac{a_2}{a_1}=\dfrac{4^{-2}}{4^{-1}}=\dfrac{1}{4}

As | r | <  1  the series is <u>convergent.</u>

When a series is convergent, we can find its sum to infinity (the limit of the series).

<u>Sum to infinity formula</u>:

S_{\infty}=\dfrac{a}{1-r}

where:

  • a is the first term in the series
  • r is the common ratio

Substitute the found values of a and r into the formula:

S_{\infty}=\dfrac{\frac{1}{4}}{1-\frac{1}{4}}=\dfrac{1}{3}

Therefore:

\displaystyle \sum^{\infty}_{n=1} 4^{-n}=\dfrac{1}{3}

Learn more about Geometric Series here:

brainly.com/question/27737241

brainly.com/question/27948054

6 0
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