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Debora [2.8K]
2 years ago
15

Which expression is equivalent to (-4p+2) - (7p-5) A. 3p-3 B. 3p+7 C.-11-3 D.-11+7

Mathematics
2 answers:
REY [17]2 years ago
6 0

Answer:

-11p + 7

Step-by-step explanation:

(-4p+2)-(7p-5)

-4p + 2 - 7p + 5

-11p +7

Katena32 [7]2 years ago
6 0

Answer:

-11p + 7

Step-by-step explanation:

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HELP!!!!!!!!!!!!!
Misha Larkins [42]

Answer:

P'(7,0)Q'(2,1) R'(12,-6)

Step-by-step explanation:

P(3,5)------>P'(3+4,5-5)

P'(7,0)

Q(-2,6)----->Q'(-2+4,6-5)

Q'(2,1)

R(8,-1)------>R'(8+4,-1-5)

R'(12,-6)

8 0
3 years ago
Which expression is equivalent to 4 - (-7
liraira [26]

Answer:

11 is the answer

Step-by-step explanation:

4 0
2 years ago
Help meeeeeee bruhfffff
Serjik [45]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>y = 15, -15</em>

▹ Step-by-Step Explanation

This is considered a 'square root' since we have to find y^2.

15 * 15 = 225

-15 * -15 = 225

Both of these values work for y, so the answer is 15, -15.

Hope this helps!

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4 0
2 years ago
Read 2 more answers
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
What is the product? 2x+8 x2 + 3x-4 x(x-4)(x-1) 20x+4) 2 (x+4)(x-4) 2x(x-1) 2x(x+4)​
guajiro [1.7K]

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

step by step

(2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x+4)

=((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(x)+((2x+8x2+3x−4x(x−4)(x−1)(20)x+4)(2)(x+4)(x−4)(2)x(x−1)(2)x)(4)

=−640x10+3840x9+4544x8−58904x7+91128x6−40608x5+128x4+512x3−2560x9+15360x8+18176x7−235616x6+364512x5−162432x4+512x3+2048x2

=−640x10+1280x9+19904x8−40728x7−144488x6+323904x5−162304x4+1024x3+2048x2

7 0
3 years ago
Read 2 more answers
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