38m².
Answer:
Solution given;
diagonal 1=8+11=19m
diagonal 2=2+2=4m
the area of a kite =½*diagonal 1*diagonal 2
=½*4*19=38m²
<u>The</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>kite</u><u> </u><u>is</u><u> </u><u>3</u><u>8</u><u>m²</u><u>.</u>
Answer:
m∠TRI = 43
Step-by-step explanation:
m∠TRI + m∠IRB = m∠TRB
3x - 5 + x + 27 = 86
3x + x - 5 + 27 = 86 {Combine like terms}
4x + 22 = 86 {Subtract 22 from both sides}
4x = 86 - 22
4x = 64 {Divide both sides by 4}
x = 64/4
x = 16
m∠TRI = 3x - 5
= 3*16 - 5
= 48 - 5
= 43
Formula = 4/3 x pi x r^3
4/3 x 3.14 x 7^3 = 1436.03
answer: a. 1436.03 cubic units
Answer:
1480 feet
Step-by-step explanation:
180yd x 2 = 360yd
change to feet: 360 x 3 = 1080 feet
200ft x 2 = 400ft
1080 + 400 = 1480ft
Answer: B
We all know that area= LxW
The width that is being shown is 8ft. The length is 20ft. Therefore, you multiply 8 x 20 which gives you 160ft squared. Hope this this helps :)
