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adelina 88 [10]
1 year ago
11

Homework! This is a stats problem I’ve been struggling with and need help thanks!!!

Mathematics
1 answer:
alexdok [17]1 year ago
4 0
Good luck u believe in you im judt commenting to get points sorry
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Step-by-step explanation:

Please, see the attached files.

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The first three terms of a sequence are given. Round to the nearest thousandth (if
tangare [24]

The 7th term of the sequence to the nearest thousandth is 223.949

<h3>What are geometric sequences?</h3>

These are sequence that increases in an exponential form.

The formula for calculating the nth term of a geometric sequence is expressed as:

Tn = ar^n-1

Given the following parameters

a = 75

r = 1.2

n = 7

Substitute the given parameter into the formula

T7 = 75(1.2)^6
T7 = 223.949

Hence the 7th term of the sequence to the nearest thousandth is 223.949

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2 years ago
Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a
krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal(\mu=1000, \sigma^{2}=100^{2})

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 1000

            \sigma = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

       z-score  =  \frac{1140-1000}{100}  =  1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal(\mu=17, \sigma^{2}=5^{2})

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 17

            \sigma = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

       z-score  =  \frac{30-17}{5}  =  2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0
3 years ago
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