A² + 2ab + b² ; Solve when a=10 & b=50
Simply plug in 10 for a and 50 for b in our given equation :)
(10)² + 2(10)(50) + (50)²
Simplify.
100 + 20(50) + 2500
Simplify.
(100 + 2500) + 1000
Simplify.
2600 + 1000
Simplify.
3600
Hope I helped! :)
Asome that’s cool do well
Answer:
the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?
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Equation:
f = (3/4)s
s-f = 4.5
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Substitute for "f" and solve for "s":
s-(3/4)s = 4.5
(1/4)s = 4.5
s = 4*4.5
s = 18 meters (height of the school)
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Since f = (3/4)s, f = (3/4)(18)
= (3/2)(9)= 13.5 meters (height of the flag pole)
===============================-step explanation: HOPE THIS HELPS
Answer:
75
Step-by-step explanation:
