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Hunter-Best [27]
3 years ago
5

Write four overloaded methods called randomize. Each method will return a random number based on the parameters that it receives

:
a. randomize() - Returns a random int between min and max inclusive. Must have two int parameters.

b. randomize() - Returns a random int between 0 and max inclusive. Must have one int parameter.

c. randomize() - Returns a random double between min and max inclusive. Must have two double parameters.

d. randomize() - Returns a random double between 0 and max inclusive. Must have one double parameter.
Computers and Technology
2 answers:
Scilla [17]3 years ago
8 0

Answer:

The Java code given below

Explanation:

//import package

import java.util.Scanner;

//Java class

class Lesson_35_Activity {

  // returns random int b/t min and max inclusive; has 2 int parameters

  public static int randomize(int min, int max) {

      int x = (int) (Math.random() * ((max - min) + 1)) + min;

      return x;

 

Yuri [45]3 years ago
6 0

Answer:

The Java code given below

Explanation:

//import package

import java.util.Scanner;

//Java class

class Lesson_35_Activity {

  // returns random int b/t min and max inclusive; has 2 int parameters

  public static int randomize(int min, int max) {

      int x = (int) (Math.random() * ((max - min) + 1)) + min;

      return x;

  }

  // returns random int b/t 0 and max inclusive; has one int parameter

  public static int randomize(int max) {

      int x = (int) (Math.random() * (max + 1));

      return x;

  }

  // returns random double b/t min and max inclusive; two double parameters

  public static double randomize(double min, double max) {

      double x = (double) (Math.random() * ((max - min) + 1)) + min;

      return x;

  }

  // returns random double b/t 0 and max inclusive; has one double parameter.

  public static double randomize(double max) {

      double x = (double) (Math.random() * (max + 1));

      return x;

  }

  // main method, which is entry point of the program

  public static void main(String[] args) {

      // object of Scanner class

      Scanner scan = new Scanner(System.in);

      // asking min and max number

      System.out.print("Enter min number : ");

      int mi = scan.nextInt();// reading min number

      System.out.print("Enter max number : ");

      int ma = scan.nextInt();// reading max number

      // checking number

      if (mi < ma) {

          System.out.println(randomize(mi, ma));// method call

          System.out.println(randomize(0, ma));// method call

          double mii = mi;

          double maa = ma;

          System.out.printf("%.2f", randomize(mii, maa));

          System.out.printf("\n%.2f", randomize(0, maa));

      } else {

          // when minimum number is greater than maximum number then display

          System.out.println("Enter min number " + mi + " should be less than max " + ma);

      }

  }

}

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Wewaii [24]

Answer:

B. Malware

Explanation:

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6 0
4 years ago
Entering the formula =SUM(C5:C18) in cell C19 will result in which of the following?
frozen [14]
Well the result shown in C19 will show the sum of all cells from C5 to C18:
ie: C5 + C6+ C7+ C8+ C9+ C10+ C11+ C12+ C13+ C14+ C15+ C16+ C17+ C18

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3 0
3 years ago
Possible consequences for plagiarism, listed in CAVA's Academic Integrity Policy, may include:
Ahat [919]

CAVA’s Academic Integrity Policy refers to Calfornia Virtual Academic’s policy book for students of their schools, which are public charter schools in the state of California.

In the handbook, it is mentioned that students who commit plagiarism will be required to re-submit the assignment during the first offence; will receive a fail grade for the assignment during the second offence; and will be withdrawn from a course or even the school during the third offence.

Thus the answer to the question is (D) all of the above.

8 0
3 years ago
Write a program that prompts the user to enter two characters and display the corresponding major and year status. The first cha
nydimaria [60]

Answer:

  1. import java.util.Scanner;  
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        System.out.print("Please enter two characters: ");
  6.        String inputStr = input.nextLine();
  7.        if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
  8.            System.out.println("Biology");
  9.        }
  10.        else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
  11.            System.out.println("Computer Science");
  12.        }
  13.        else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
  14.        {
  15.            System.out.println("Information Technology and Systems");
  16.        }
  17.        else{
  18.            System.out.println("Invalid major");
  19.        }
  20.        int num = Character.getNumericValue(inputStr.charAt(1));
  21.        if(num >= 1 && num <= 4){
  22.            switch (num){
  23.                case 1:
  24.                    System.out.println("freshman");
  25.                    break;
  26.                case 2:
  27.                    System.out.println("sophomore");
  28.                    break;
  29.                case 3:
  30.                    System.out.println("junior");
  31.                    break;
  32.                case 4:
  33.                    System.out.println("senior");
  34.                    break;
  35.            }
  36.        }
  37.        else{
  38.            System.out.println("Invalid year status");
  39.        }
  40.    }
  41. }

Explanation:

The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.

The part 2 is to validate the year status to make sure it only fall within the range of 1-4  (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.

4 0
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White raven [17]

Answer is: Dispersants


Explanation:

Dispersants keep contaminants (e.g. soot) suspended in the oil to prevent them from coagulating. Anti-foam agents inhibit the production of air bubbles and foam in the oil which can cause a loss of lubrication, pitting, and corrosion where entrained air and combustion gases contact metal surfaces.

So that's why the answer is: Dispersants

7 0
3 years ago
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