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svet-max [94.6K]
3 years ago
7

Which social media marketing concept engages visitors, getting them to revisit your website and tying them to offline events for

the benefit of your company?
a. Call to Action


b. return on investment


c. customer engagement


d. bounce rates
Computers and Technology
2 answers:
STALIN [3.7K]3 years ago
7 0
I'm not good with this stuff but it might be (A)
Mariana [72]3 years ago
7 0

if you are on plato then it is for sure A.

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Human systems integration (hsi), a supportability issue that every program should consider, addresses such factors as accessibil
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I guess the word in the blank is Standardization.

Human systems integration (HSI), a supportability issue that every program should consider, addresses such factors as accessibility, visibility, testability, and Standardization.


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What are the advantages of renting a home over buying a home? What are some disadvantages?
weqwewe [10]
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Complete the statement below with the correct term.
g100num [7]

Answer:

boot disk

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8 0
3 years ago
In the simulation, player 2 will always play according to the same strategy. The number of coins player 2 spends is based on wha
baherus [9]

The simulation, player 2 will always play according to the same strategy.

Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

  • You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.

#include <bits/stdc++.h>  

using namespace std;

bool getplayer2move(int x, int y, int n)  

{

   int dp[n + 1];  

   dp[0] = false;  

   dp[1] = true;  

   for (int i = 2; i <= n; i++) {  

       if (i - 1 >= 0 and !dp[i - 1])  

           dp[i] = true;  

       else if (i - x >= 0 and !dp[i - x])  

           dp[i] = true;  

       else if (i - y >= 0 and !dp[i - y])  

           dp[i] = true;  

       else

           dp[i] = false;  

   }  

   return dp[n];  

}  

int main()  

{  

   int x = 3, y = 4, n = 5;  

   if (findWinner(x, y, n))  

       cout << 'A';  

   else

       cout << 'B';  

   return 0;  

}

8 0
3 years ago
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