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3 years ago

What is the base for a hexadecimal number system?

Computers and Technology

1 answer:

miskamm [114]3 years ago

5 0

The base for a hexadecimal number system is 16

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Identify what algorithm or concept the following code relates to. void Sort(int array[], int tempArray[], int left, int right) {

galina1969 [7]

Answer:

Binary sort

Explanation:

Binary sort is one of the fastest search techniques used on arrays and other iterable data types. It algorithm sorts the array in ascending order then gets the item in the middle from which it divides the array to be searched in two parts. If the searched term is less than the mid item, then it is searched for in the first part, else it would be in the second.

4 0

2 years ago

Integral 3t+ 1 / (t + 1)^2

Verizon [17]

Answer:

$3ln|t+1|+\frac{2}{t+1} +C$

Explanation:

We'll be using u-substitution for this problem.

Let

$u=t+1\\du=dt$

Substitute

$\int\limits {\frac{3u-2}{u^2}} \, du$

Split the fraction

$\int\limits {\frac{3u}{u^2} } \, du -\int\limits {\frac{2}{u^2} } \, du$

Move the constants out

$3\int\limits {\frac{u}{u^2}du -2\int\limits {u^{-2}} \, du$

Simplify

$3\int\limits {\frac{1}{u}du -2\int\limits {u^{-2}} \, du$

Integrate

$3ln|u|+\frac{2}{u} +C$

Substitute

$3ln|t+1|+\frac{2}{t+1} +C$

5 0

3 years ago

Implement the simulation of a biased 6-sided die which takes the values 1,2,3,4,5,6 with probabilities 1/8,1/12,1/8,1/12,1/12,1/

hjlf

Answer:

see explaination

Explanation:

import numpy as np

import matplotlib.pyplot as plt

a = [1, 2, 3, 4, 5, 6]

prob = [1.0/8.0, 1.0/12.0, 1.0/8.0, 1.0/12.0, 1.0/12.0, 1.0/2.0]

smls = 1000000

rolls = list(np.random.choice(a, smls, p=prob))

counts = [rolls.count(i) for i in a]

prob_exper = [float(counts[i])/1000000.0 for i in range(6)]

print("\nProbabilities from experiment : \n\n", prob_exper, end = "\n\n")

plt.hist(rolls)

plt.title("Histogram with counts")

plt.show()

check attachment output and histogram

4 0

3 years ago

: For each of the following words identify the bytethat is stored at lower memory address and the byte that is storedat higher m

Aloiza [94]

Answer:

In a <u>little endian computer</u> -The data's least substantial byte is put at the lower address byte. The remaining information will be put in memory in order in the next three bytes.

a)1234

4 is placed at the least significant bits,so this byte stored at lower memory address.

1 is placed at the most significant bits,so this byte stored at higher memory address.

b) ABFC

C is placed at the least significant bits,so this byte stored at lower memory address.

A is placed at the most significant bits,so this byte stored at higher memory address.

c) B100

0 is placed at the least significant bits,so this byte stored at lower memory address.

B is placed at the most significant bits,so this byte stored at higher memory address.

d) B800

0 is placed at the least significant bits,so this byte stored at lower memory address.

B is placed at the most significant bits,so this byte stored at higher memory address.

5 0

3 years ago

HAve a good week lads, good luck on work :D

Leno4ka [110]

Answer:

v; its alright.

Explanation: none v;

8 0

3 years ago

Read 2 more answers