Answer:
30 Chairs
Step-by-step explanation:
I will solve this problem using algebra and try to explain in detail.
We can form two equations with the information given to us.
Firstly, 5 times a length of chairs (I will call this unknown length of chairs x), plus 5 left over chairs, equals the total number of chairs (I will call the total number of chairs y).
5x + 5 = y
Secondly, 3 times a length of chairs (I will call this unknown length of chairs x), plus 15 left over chairs, equals the total number of chairs (I will call the total number of chairs y).
3x + 15 = y
Since both equations are equal to y, they are equal to each other
5x + 5 = 3x + 15
Take 5 away from both sides of the equals, and take away 3x from both sides of the equals
5x - 3x = 15 - 5
2x = 10
Divide both sides by 2
x = 5 chairs
Put this back into either the first equation or the second to solve for y
3 (5) + 15 = y
15 + 15 = y
y = 30 chairs
Answer:
B
Step-by-step explanation:
There are 400 employees and 72% of that is .72 so you multiply 400 x .72 =288 so there are 288 part-time employees (eliminate for the remainder) 400-288 = 112
No it is not always a mixed number if you add two mixed numbers
The quantity that is present after 2000 years will be A. 7.851 grams.
<h3>How to calculate the quantity?</h3>
From the information given, initially at t = 0, the quantity is 10 grams.
After 2000 years, the appropriate quantity will be:
Q(2000) = 10 (1/2) × (2000/5730)
Q(2000) = 7.851 grams.
In conclusion, the correct option is A.
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