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svetoff [14.1K]
3 years ago
12

Find xy when x(-7,10) and y(3,4)

Mathematics
1 answer:
Gnoma [55]3 years ago
4 0

Answer:

Distance xy = 11.66 unit (Approx)

Step-by-step explanation:

Given:

x(-7,10)

y(3,4)

Find:

Distance xy

Computation:

Distance = √(x2-x1)²+(y2-y1)²

Distance xy = √(3+7)²+(4-10)²

Distance xy = √ 100 + 36

Distance xy = 11.66 unit (Approx)

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Step-by-step explanation:

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Step-by-step explanation:

Use FOIL:

y^4 + \frac{-14}{5}y^2 + \frac{5}{7}y^2 + \frac{-70}{35}

Make  \frac{-14}{5}y^2 and \frac{5}{7}y^2 have the same numerator:

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Then add like terms and simplify:

y^4 + \frac{-98}{35}y^2 + \frac{25}{35} y^2 + \frac{-70}{35}

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Answer:

85-86%

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36 x 100 = 42 x X

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X=85.71

7 0
2 years ago
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