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Anon25 [30]
3 years ago
6

Which represents the solution(s) of the system of equations, y = x2 – 2x – 15 and y = 8x – 40? Determine the solution set algebr

aically.
(–5, –80)
(5, 0)
(5, 0) and (–5, –80)
no solutions
Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer:

(5, 0 )

Step-by-step explanation:

Given the 2 equations

y = x² - 2x - 15 → (1)

y = 8x - 40 → (2)

Substitute y = x² - 2x - 15 into (2)

x² - 2x - 15 = 8x - 40 ( subtract 8x - 40 from both sides )

x² - 10x + 25 = 0 ← in standard form

(x - 5)² = 0 ← in factored form, thus

x - 5 = 0 ⇒ x = 5

Substitute x = 5 into (2) for corresponding value of y

y = 8(5) - 40 = 40 - 40 = 0

Solution is (5, 0 )

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The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect
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Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

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AB = DC

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Formula

Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}

Now the points  A(−3, 4) and  B(7, 2)

AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}

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CD= 2\sqrt{26}\units

Now the points

A (−3, 4) , D (−4, −1)

AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}

AD = \sqrt{(-1)^{2} +(-5)^{2}}

AD = \sqrt{1 + 25}

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Thus

BC = \sqrt{26}\units  

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

Length = 2\sqrt{26}\ units

Breadth = \sqrt{26}\ units  

Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})

Perimeter\ of\ rectangle = 2(3\sqrt{26})

Perimeter\ of\ rectangle = 6\sqrt{26}

\sqrt{26} = 5.1 (Approx)

Perimeter\ of\ rectangle = 6\times 5.1

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

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