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Assoli18 [71]
3 years ago
7

Given X= 5+ V16 select the value(s) of x. Check

Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0

Answer:

x = 9\ or\ x = 1

Step-by-step explanation:

Given

x = 5 + \sqrt{16}

Required

Find the value of x

x = 5 + \sqrt{16}

We start by taking the square root of 16; Square root of 16 is +4 or -4; So, we have:-

x = 5 \±4

The expression above can be split into two; This is as follows

x = 5 + 4\ or\ x = 5 - 4

x = 9\ or\ x = 1

<em>Hence, the solution to </em>x = 5 + \sqrt{16}<em> is B. 1 and C. 9</em>

Ray Of Light [21]3 years ago
4 0

Answer:

its b and c

Step-by-step explanation:

the guy who answered first said so

also i just did it

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marshall27 [118]

Answer:

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8 0
3 years ago
Match the expression with its name.
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6 0
4 years ago
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
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The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

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but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


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Answer: 24 \sqrt{3}+72   cm^2

4 0
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Answer:

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