6x - 3 > 4x + 5 |add 3 to both sides
6x > 4x + 8 |subtract 4x from both sides
2x > 8 |divide both sides by 2
x > 4 ⇒ x ∈ (4; ∞)
subtract 6.4 from 25 = 1.3c + 18.6
The answer is -40 because if you get rid of the negative sign and add instead of subtract... you get 40 so its like adding in the opposite direction.
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
