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natita [175]
3 years ago
8

Convert 11 years to hours

Mathematics
2 answers:
yan [13]3 years ago
5 0

Answer:

96360

Step-by-step explanation:

search hours a month then multiply that by 12

ki77a [65]3 years ago
5 0
The answer is 96,360hrs


If you have to round it it’s is 96,000
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How do I solve for q?
german
The answer should be q=0.522
4 0
4 years ago
The circumference of a circle is 7π m. What is the area of the circle? ​3. 5π​ m² ​12. 25π​ m² ​14π​ m² ​49π​ m².
Juliette [100K]

Area of the circle is the area covered by that circle. The area of the circle whose circumference is 7π m is 12.25π m².

<h3>What is the area of a circle?</h3>

The area of the circle is the area covered by that circle. It is given by the formula,

\text{Area of the circle}=\pi r^2

where r is the radius of the circle.

As it is given that the circumference of a circle is 7π m. Therefore, the radius of the circle can be written as,

\text{Circumference of the circle} = 2\pi r

7 \pi = 2 \pi r\\\\r = 3.5\rm\ m

Now, we know the formula of the area of a circle, therefore, the area of the circle can be written as,

\text{Area of the circle}=\pi r^2

                           = \pi \times (3.5)^2\\\\= 12.25\pi\rm \ m

Hence, the area of the circle whose circumference is 7π m is 12.25π m².

Learn more about Area of Circle:

brainly.com/question/1238286

5 0
3 years ago
Suppose that a rectangle has an area of 54 square meters. Express the perimeter P as a function of the length x of one of the si
Lapatulllka [165]

Answer:

P(x) = 2\left(x+\dfrac{54}{x}\right)

Step-by-step explanation:

The area of the rectangle can be written as:

A = x*h

here, x is one side length, and h is the other side length. This area is said to be equal to 54 square meters.

54 = x*h

The perimeter of a rectangle can be written as:

P = 2x+2h

To express perimeter only in terms of x (in other words making it a function P(x)). we need to replace h. And this can be done by using the equation of area that we derived earlier.

54 = x*h

h=\dfrac{54}{x}

now we can substitute this 'h' into our equation of the perimeter.

P = 2x+2\left(\dfrac{54}{x}\right)

P = 2\left(x+\dfrac{54}{x}\right)

and voila! we have expressed P in terms of x only.

this can be written as P as a function of x as:

P(x) = 2\left(x+\dfrac{54}{x}\right)

6 0
4 years ago
An article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and
Marta_Voda [28]

Answer:

The 95% confidence interval for the proportion of all dies that pass the probe is (0.637, 0.733).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

356 dies were examined by an inspection probe and 244 of these passed the probe.

This means that n = 356, \pi = \frac{244}{356} = 0.685

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.685 - 1.96\sqrt{\frac{0.685*0.315}{356}} = 0.637

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.685 + 1.96\sqrt{\frac{0.685*0.315}{356}} = 0.733

The 95% confidence interval for the proportion of all dies that pass the probe is (0.637, 0.733).

4 0
3 years ago
A chef at a restaurant uses pounds of butter each day. About how many grams of butter does the chef use each​ day? Use the conve
Vadim26 [7]

Complete question :

A chef at a restaurant uses 12 pounds of butter each day. About how many grams of butter does the chef use each day? use the conversion factors 16 oz/1 lb and 28.35 grams/1oz

Answer:

5,424 grams

Step-by-step explanation:

To convert using the conversion factor :

Number of pounds of butter * (16 oz/1) * (28.35) /1

Hence,

12 * 16oz/ 1 * 28.35/1

(12 * 16 * 28)

= 5,424 grams

7 0
3 years ago
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