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Phoenix [80]
3 years ago
6

Please help me and I will thank you

Mathematics
1 answer:
uysha [10]3 years ago
6 0

The value a = 4 will always yield a correct answer.

We know this by solving for a. If we do this, we will get the number needed.

a(x + 3) < 5x + 15 - x -----> simplify like terms

a(x + 3) < 4x + 15 -----> divide by x + 3

a < 4 + 3/(x + 3)

Since a is less than 4 plus a number, we know that a will always be less than 4. So we can use 4 as the number for all real solution.

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Suppose n=6 , m=2 , z1 is the average of the elements of x , and z2 is the average of the first three elements of x minus the av
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Answer:

See step by step explanations fir answers.

Step-by-step explanation:

Given that;

n=6 , m=2 , z1 is the average of the elements of x , and z2 is the average of the first three elements of x minus the average of fourth through sixth elements of x

So, Let d=n∧28, d′=n∧22.

We have nd=10, nd′=20n

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On the other hand, d is a divisor of 28, and above shows d′ is, too. As it is also a divisor of 22, the only possibilities are d′=1, d′=2, corresponding to d=2, d=4.

However, if d=2, n=20, and 20∧28=4, not 2. So the only solution is d=4, and n=40.

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