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2 years ago

5m-1=4m+5 ASAP thank you

Mathematics

1 answer:

d1i1m1o1n [39]2 years ago

7 0

The answer is m=6. You do 5m-4m=5+1 and get m=6.

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Which inequality represents the value of x that ensures triangle abc exists?

olasank [31]

Answer:

Option A.

Step-by-step explanation:

According to triangle inequality theorem, a triangle exists if the sum of two sides is greater that third side.

Apply this theorem on each combination.

Case I: $(2x+4)+6x>18$

$8x+4>18$

$8x>14$

$x>\dfrac{14}{8}$

$x>\dfrac{7}{4}$ ...(1)

Case II: $(2x+4)+18>6x$

$2x+22>6x$

$22>4x$

$\dfrac{22}{4}>x$

$\dfrac{11}{2}>x$ ...(2)

Case III: $6x+18>2x+4$

$6x-2x>4-18$

$4x>-14$

$x>-\dfrac{14}{4}$

$x>-\dfrac{7}{2}$ ...(3)

On combining (1), (2) and (3), we get

$\dfrac{7}{4}$

Therefore, the correct option is A.

3 0

2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

2 years ago

The data in which table represents a linear function that has a slope of zero? A 2-column table with 5 rows. Column 1 is labeled

lisov135 [29]

Answer: A 2-column table with 5 rows. Column 1 is labeled x with entries negative 5, negative 4, negative 3, negative 2, negative 1. Column 2 is labeled y with entries 5, 5, 5, 5, 5.

8 0

2 years ago

State the degree of the polynomial. 2x3 - x4 + 5x2 - x

labwork [276]

The degree is 4 because it is the largest exponent out of all the variables.

8 0

2 years ago

The price p in dollars and the quantity x sold of a certain product obey the demand equation -1/5x+100 (0≤ x ≤ 500)

olga nikolaevna [1]

Answer:

See below

Step-by-step explanation:

We have:

p = -1/5x + 100 = -0.2x + 100

a) The revenue is:

R = px
R = x( -0.2x + 100)
R= -0.2x² + 100x

b) x = 200, find R:

R = -0.2(200²) + 100(200) = 12000

c) This is a quadratic function and the maximum value is obtained at vertex.

x = -100/(-0.2*2) = 250 is the required quantity

d) The max revenue is obtained when -0.2x + 100 at max:

The maximum possible is p = 100 when x = 0

5 0

2 years ago

Read 2 more answers