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dusya [7]
3 years ago
15

Please please help me out!!!

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer: 8.50 dollars

The result is positive, so this is a gain (instead of a loss)

====================================

Explanation:

Focus on the "stock JKL" row only when it comes to the percentages we'll use. We need to convert them to decimal form

15% ---> 0.15

65% ---> 0.65

20% ---> 0.20

I just moved the decimal point over 2 spots, or you can divide by 100 (eg: 15% = 15/100 = 0.15)

Multiply each of these values by their corresponding loss or gain. Use negative numbers for losses

15% chance of losing $25 ---> 0.15*(-25) = -3.75

65% chance of winning $5 ---> 0.65*(5) = 3.25

20% chance of winning $45 ---> 0.20*(45) = 9

Now add up those results: -3.75+3.25+9 = 8.50

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Step-by-step explanation:

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3 years ago
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On Thursday, Movietown Theater made \dfrac45
Oliga [24]

Answer:

11 Pounds

Step-by-step explanation:

Let the total pounds of popcorn made by Movietown Theater=x

On Thursday, they made \dfrac{4}{5} of their popcorn with butter.

The remaining fraction of the butter will be: 1-\dfrac{4}{5} =\dfrac{1}{5}

The remaining 35.2 Ounces was made without butter.

Let us convert from ounces to pounds.

  • 1 Ounce =0.0625 Pound
  • 35.2 Ounce=35.2 X 0.0625 =2.2 Pounds

Therefore:

\dfrac{1}{5} \text{of the total pounds of popcorn} = 2.2\\\dfrac{1}{5}* x = 2.2\\x=2.2* 5\\x=11 $ Pounds

Therefore, the total pounds of popcorn made by Movietown Theater on Thursday is 11 Pounds.

8 0
3 years ago
a gym has 275 members 40% are bronze members 28% are silver members the rest are good work out the gold members
statuscvo [17]
STEP 1:
Find % of gold members. Subtract the known % of bronze and silver members from 100%.

x= percent of gold members

x= 100% - (40% +28%)
x= 100% - 68%
x= 32% percent of gold members


STEP 2:
Find number of gold members. Multiply % of gold members by the total numbers of members (275).

x= # of gold members

x= 275 * 32%
x= 275 * 0.32
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Hope this helps! :)
6 0
4 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean 1263 and a stan
DENIUS [597]

Answer:

(a) The 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b) The number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c) The inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of chocolate chips in a bag of chocolate chip cookies.

The random variable <em>X</em> is normally distributed with mean, <em>μ </em>= 1263 and a standard deviation, <em>σ </em>= 117.

(a)

Compute the 29th percentile for the number of chocolate chips in a bag as follows:

P (X < x) = 0.29

⇒ P (Z < z) = 0.29

The value of <em>z</em> for the above probability is, <em>z</em> = -0.55.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sogma}\\-0.55=\frac{x-1263}{117}\\x=1263-(117\times 0.55)\\x=1198.65

Thus, the 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b)

According to the Empirical rule 95% of the normally distributed data lies within 2 standard deviations of the mean.

P (μ - σ < X < μ + σ) = 0.95

P (1263 - 117 < X < 1263 + 117) = 0.95

P (1146 < X < 1380) = 0.95

Thus, the number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c)

The inter-quartile range of the normal distribution is:

IQR = 1.349 <em>σ</em>

Compute the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies as follows:

IQR = 1.349 <em>σ</em>

      = 1.349 × 117

      = 157.833

Thus, the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

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