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3 years ago

Helpppppppppppppppppppppppp

Mathematics

1 answer:

pogonyaev3 years ago

3 0

Answer:

I'm not sure about "11" but 12. is "by the definition of right angles", and 16. is "by the SAS(side angle side) congruency theorem"

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Which expression is equivalent to the expression below? <br><br> (4x + 2y - z) - (x - y + 7)

Margaret [11]

Answer:

3x+3y−z−7

Step-by-step explanation:

"Let's simplify step-by-step.

4x+2y−z−(x−y+7)

Distribute the Negative Sign:

=4x+2y−z+−1(x−y+7)

=4x+2y+−z+−1x+−1(−y)+(−1)(7)

=4x+2y+−z+−x+y+−7

Combine Like Terms:

=4x+2y+−z+−x+y+−7

=(4x+−x)+(2y+y)+(−z)+(−7)"(Mathpapa)

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3 years ago

He temperature moreased by 8' Fahrenheit

kompoz [17]

it is B The temperature started at 78°F and increased by 6°F Then the temperature increased by 5°F

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2 years ago

Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

Learn more about probability here

brainly.com/question/24756209

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7 0

2 years ago

I WILL GIVE BRAINLEST!!!

lukranit [14]

Answer:

Step-by-step explanation:

To find the zeros of this polynomial, set the polynomial equal to zero, and then set each of the factors equal to zero separately. Solve each equation for x:

x - 1 = 0 yields x = 1. The x-intercept is (1, 0).

x + 3 = 0 yields x = -3. The x-intercept is (-3, 0).

2x + 1 = 0 yields x = -1/2 The x-intercept is (-1/2, 0)

4 0

3 years ago

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Please help the assignment is overdue. :(

Pachacha [2.7K]

The answer would be No solution

3 0

3 years ago

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