Answer:
resultant vector = 25.2
Step-by-step explanation:
we apply cosine theorem
Answer:
Step-by-step explanation:
Team A : the mean height (average) is :
(75 + 64 + 78 + 65 + 68) / 5 = 350/5 = 70 inches
the range is highest number minus lowest number ...78 - 64 = 14
Team B : the mean height (average) is :
(76 + 68 + 70 + 74 + 67) / 5 = 355/5 = 71 inches
the range is : 76 - 67 = 9
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A). nope....it mentions nothing of the weight
B) nope....mean height of team A is not greater
C) nope...because that 75 inch player on team A
D) THIS ONE....the range for team A is greater then the range for team B
To get an expression relating to x you need to have x alone on one side of your equation. ie x =
<span>Try this: </span>
<span>rx - st = r </span>
<span>remove st from the rx side </span>
<span>rx = r + st </span>
<span>now divide by r </span>
<span>x = (r + st)/r </span>
<span>You now have your expression relating to x</span>
(A) The mean is 82
(B) The mean absolute deviation is approximately 9.71
(D) The IQR is 11
<u>Explanation:</u>
<u />
(A) 89, 87, 54, 78, 87, 99, 80
Mean of the data = 
Therefore, mean of the data is 82
(B) The mean absolute deviation, MAD is
data - 54, 78, 80, 87, 87, 89, 99
Mean of the data, x' is 82
|x - x'| : 54 - 82 = 28
78 - 82 = 4
80 - 82 = 2
87 - 82 = 5
87 - 82 = 5
89 - 82 = 7
99 - 82 = 17
Total of |x - x'| = 68
MAD = |x - x'| / n
MAD = 68/7
MAD = 9.71
(D) IQR is the interquartile range
Data = 54, 78, 80, 87, 87, 89, 99
IQR = median of lower quartile range - median of upper quartile range
IQR = 89 - 78
IQR = 11
