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andrew11 [14]
3 years ago
7

The computer game Peter wants to buy will cost at least $50 and not more than $70. He earns $3 an hour running errands for his g

randmother. Which inequality shows the number of hours, n, he will have to work to pay for the game?
A. 3n ≥ 20
B. n/3 ≥ 20
C. 50 ≤ 3n ≤ 70
D. 50 ≤ n/3 ≤ 70
Mathematics
2 answers:
taurus [48]3 years ago
7 0
The answer is C, where 50 is less than or equal to the amount of money he earned per hour which will have to be less than 70
Lunna [17]3 years ago
6 0

Answer:

The answer to your question is C

Just try it out

- have a nice day, be safe & healthy -

- peace out -

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Solve 3y - 15 = y+1 with steps shown
bija089 [108]

Answer:

y = 8

Step-by-step explanation:

Hello!

We can solve for y by isolating it.

<h3>Solve for y</h3>
  • 3y - 15 = y + 1
  • 3y - 15 - y = y +1 - y
  • 2y - 15 = 1
  • 2y - 15 + 15 = 1 + 15
  • 2y = 16
  • y = 16/2
  • y = 8

The value of y is 8.

4 0
2 years ago
Read 2 more answers
Will someone help with this ! I was allowed a retry for it and I don’t know how to do it
pashok25 [27]

Answer:

\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697

Step-by-step explanation:

6 0
3 years ago
Jaclyn estimates that the square root of 50 in the following way: √50 = 2√25 = 2*5 = 10
Harman [31]

Answer:

Jacklyn is wrong because

\sqrt{50}   \ne2 \sqrt{25 }

Step-by-step explanation:

We have that :Jaclyn estimates that the square root of 50 in the following way:

\sqrt{50}  = 2 \sqrt{25}

\sqrt{50}  = 2 \times 5

\sqrt{50}  = 10

Jacklyn is wrong because she made an error at

\sqrt{50}  = 2  \sqrt{25}

The correct expression is

\sqrt{50}  = \sqrt{2 \times 25}

This gives:

\sqrt{50}  = \sqrt{ 25}  \times  \sqrt{2}

\sqrt{50}  =5 \sqrt{2}

8 0
3 years ago
Twice the product of the cube of a and the square of b
arlik [135]

For this case we have to rewrite the given expression algebraically:

the cube of a, is represented as: a ^ 3

the square of b, is represented as:b ^ 2

Thus, the product of both expressions is:

(a ^ 3 * b ^ 2)

And twice the product is represented as:

2 (a ^ 3 * b ^ 2)

Answer:

2 (a ^ 3 * b ^ 2)

6 0
3 years ago
Can someone help me w work shown or like how to do it?
Masteriza [31]
Basically you explain what your answer is and how you got it then you should be good!
8 0
3 years ago
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