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Alex17521 [72]
3 years ago
5

Sally begins hiking at an elevation of 224 ft then she descends 131 ft and climbs 67 feet higher than her current position she t

hen descends 163 ft write an addition sentence to describe the situation then determine and interpret the sum
Mathematics
1 answer:
Temka [501]3 years ago
3 0

Answer:

Sally ends at 3 feet below zero point.

Step-by-step explanation:

Let be h the height with respect to zero point, which is represented by the following sum:

h = \Sigma_{i=1}^{n} h_{i}

Where:

h_{i} - i-th travelled height, measured in feet.

In addition, positive sign means ascension, whereas negative sign means descent.

The statement can be translated into the following mathematical identity:

h = h_{1}+h_{2}+h_{3}+h_{4}

h = 224\,ft+(-131\,ft)+67\,ft -163\,ft

h = -3\,ft

Sally ends at 3 feet below zero point.

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Answer:  197.292

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12

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2 years ago
I NEED HELP ASAP<br> QUESTION BELOW
Gekata [30.6K]

Answer:

Circumference ≈ 50.27

Area ≈ 201.06

Step-by-step explanation:

The circumference of a circle is 2\pi r while the area of the circle \pi r^{2}

Since the diameter is the radius multiplied by 2, the radius of the circle is 8. So substituting 8 for r, the circumference is 2 × \pi × 8, which is approximately 50.27 (rounded to the nearest hundredth) and the area of the circle would be \pi × 8². 8² is 64 so 64 times pi is approximately 201.06 (rounded to the nearest hundredth)

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2 years ago
Math gram question please help thanks
mezya [45]
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7 0
3 years ago
Julian walked 6/10 of a mile to his friends house and another 35/100 mile to the store. He walked 1/4 of a mile back home. Julia
AveGali [126]

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 1\frac{1}{5} \text{ or } \frac{6}{5} miles.

<u>Solution:</u>  

Given that,

  • Julian walked 6/10 of a mile to his friends house
  • Another 35/100 mile to the store
  • He walked 1/4 of a mile back home

To find total distance walked by Julian we have to add the above stated values. That is, \frac{6}{10} +\frac{35}{100} +\frac{1}{4}

Factors of 10 = 5\times2

Factors of 100 = 5\times2\times5\times2

Factors of 4 = 2\times2

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}

\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}

Which can also be written as 1\frac{1}{5}.

So, from the above calculation it can be said that Julian walked 1\frac{1}{5} \text{ miles }.

3 0
3 years ago
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