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krok68 [10]
3 years ago
13

A tree dimensional figure has _______, ___________, __________, ​

Mathematics
1 answer:
Anton [14]3 years ago
5 0

Answer: faces, edges, and vertices.

Also height, width and depth.

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Sierra applies a coat of epoxy paint to the four sides and floor of a rectangular swimming pool. The pool is 4 feet deep, 18 fee
Brilliant_brown [7]

Answer:

4 gallons of paint

Step-by-step explanation:

We solve using the formula for surface area of rectangular prism.

A=2(wl+hl+hw)

Where:

w = Width

h = Height

l = Length

The pool is 4 feet deep, 18 feet long, and 12 feet wide.

Hence,

=2 × (12 × 18 + 4 × 18 + 4 ×12)

=672 square feet

One gallon of paint covers 155 square feet.

Hence,

155 square feet = 1 gallon of paint

672 square feet = x

Cross Multiply

155 square feet × x = 672 square feet × 1 gallon of paint

x = 672 square feet × 1 gallon of paint/ 155 square feet

x = 4.335483871 gallons of paint

Therefore, based on the calculation above, approximately to the nearest whole number, Sierra uses 4 gallons of paint

4 0
3 years ago
Rewrite 3√5^2 with a rational exponent.
Law Incorporation [45]

Answer:

C. 5 2/3

Step-by-step explanation:

3 0
3 years ago
Based on the Pythagorean Theorem, which of
aleksley [76]

Answer:

G is not TRUE.

Step-by-step explanation:

using the law A+B = B+A

PYTHAGOREAN THEOREM

A²+B² =C² is equal to B² +A² = C²

So for A²,

B² - c² = A. remember if a positive number move from the left to the right over an equal sign it becomes negative and vice versa

B²

C² - A²= B²

6 0
2 years ago
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
<span>
</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
</span>
8 0
3 years ago
What percent of 120 is 42​
poizon [28]

35%.

42/120 = 0.35.

0.35 X 100 = 35. That tells us 42 is 35% of 120.

6 0
3 years ago
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