The graph of f(x) = (0.2)(x^4 + x^3 – 12x^2) is shown. On a coordinate plane, a graph decreases through (4, 0) to (3, negative 1

Question

3 years ago

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The graph of f(x) = (0.2)(x^4 + x^3 – 12x^2) is shown. On a coordinate plane, a graph decreases through (4, 0) to (3, negative 1

1) and then curves up to (0, 0). It then curves down to (2, negative 4), and curves up through (3, 0). Based on the graph, what is the solution to (0.2)(x^4 + x^ 3 – 12x^2) < 0?

Mathematics

1 answer:

attashe74 [19] · Answer 1 · 2022-08-15T12:25:36+03:00

attashe74 [19]3 years ago

5 0

Answer: The answer is A. (-4,0) U (0,3) on edgenuity

Step-by-step explanation:

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