How is light energy processed in the light reaction of photosynthesis? through sugar glycolysis

4. To which planet did the rover Curiosity travel?

dimulka [17.4K]

Answer:

Mars

Explanation:

Sent by SpaceX, Curiosity traveled Mars and took many useful pictures and captured its space.

7 0

4 years ago

Two dihybrid pea plants (both tall and with purple flowers) are mated. The cross resulted in 9866 progeny, of which 5550 were ta

d1i1m1o1n [39]

Answer:

<h2>616 Short with white flower </h2><h2>1850 Tall with white flower </h2><h2>1850 Short with purple flower</h2>

Explanation:

A dihybrid cross is in which two genes of two different traits are crossed

As given, two dihybrid pea plants (tall with purple flower) are mated, resulting 5550 out of 9866 were tall with purple.

T= tall

t= short,

P= purple,

p= white;

So genotype of parents are TtPp ; T is dominant over t, P is dominant over p.

Crossing between two parens= TtPp × TtPp

so gamets are = parent 1: TP, Tp, tP, tp and parent 2: TP, Tp, tP, tp

Hence the four different gametes formed.

Now arrange the gametes on the top and left side of a Punnett square it'll genotypically results into different combinations, by which phenotypic ratios can be calculated.

offspring are = TTPP, TTPp, TtPP, TtPp....................TTpp, Ttpp.....ttPP, ttPp.......ttpp

(T_P_)= Tall with purple flower,

(T_pp)= tall with white flower,

(ttP_)= short with purple flower,

(ttpp)= short with white flower.

so it show 12:3:3:1 ratio'

Phenotypic classes are:

616 Short with white flower

1850 Tall with white flower

1850 Short with purple flower

8 0

3 years ago

How do our cells form<br> carbon dioxide?

Phoenix [80]

Answer:

the process of cellular respiration

Explanation:

oxygen releases heat energy and carbon dioxide

7 0

3 years ago

Read 2 more answers

In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive

aev [14]

Answer:

In the next generation of 4000 children, 1680 of them will be heterozygous for the eye colour.

Explanation:

There's a population of 2500, 2275 of with have brown eyes and 225 blue eyes. <u>Let's call the dominant allele associated with brown colour "B" and the recessive allele associated with blue colour "b"</u>. So the possible genotypes are BB, Bb and bb, being BB and Bb brown eyed individuals and bb blue eyed individuals.

If the population it's in Hardy-Weinberg equilibrium, it means genotypic and allelic frequencies don't change from one generation to the following.

From the information given, we can calculate both allelic and genotypic frequencies.

First, we know that the frequency of the genotype bb it's the amount of blue eyed individuals over the total population.

f(bb)=225/2500=0.09

Additionally we know the allelic frequencies can be related to the genotypic ones when the population it's in Hardy-Weinberg equilibrium. Particularly we can say:

f(bb)=[f(b)]^2 => f(b)=[f(bb)]^(1/2)= 0.3 <em>(square root of f(bb)).</em>

Also, we can calculate the frequency of the B allele, as the probability of all alleles of the gene sum 1. In other words:

f(b)+f(B)=1 => f(B)=1 - f(b) = 1 - 0.3 = 0.7

So far, we have calculated the allelic frequencies, f(b)=0.3 and f(B)=0.7.

Now we can calculate the genotypic frequencies, using the equations of the Hardy-Weinberg equilibrium.

f(bb)=[f(b)]^2 => f(bb)=0.3^2=0.09
f(Bb)=2*f(B)*f(b) => f(Bb)=2*0.7*03=0.42
f(BB)=[f(B)]^2 => f(BB)=0.7^2=0.49

Finally, knowing that there are 4000 children in the next generation, to know how many of them are expected to be heterozygous for the eye colour, we should multiply the number of children for the probability of being heterozygous for the eye colour (which is the genotypic frequency for the genotype Bb).

Nº of heterozygous individuals = f(Bb)*total population= 0.42*4000

=> Nº of heterozygous individuals =1680

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3 0

3 years ago

What is insulin's structure?<br> a.quaternary<br> b.secondary<br> c.primary<br> d.tertiary

saw5 [17]

Hello!
The correct answer is C. We know this because it consists of an incredibly simple polypeptide chain that has a continuous pattern. The rest of the choices represent complex chains.
I hope I helped!

5 0

4 years ago