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3 years ago

Explain how to find the x-intercept of the graph of y = 4x - 2.

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

There are two ways to do this. The first of which is the algebraic method. Plug in y = 0 and solve for x.

y = 4x - 2

0 = 4x - 2 ... y is replaced with 0

4x-2 = 0

4x-2+2 = 0+2 ... we add 2 to both sides

4x = 2

4x/4 = 2/4 .... divide both sides by 4

x = 1/2

x = 0.5

The x intercept is x = 1/2 or x = 0.5

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The other approach is to graph the equation y = 4x-2, and mark where the line crosses through the x axis. You should find it crosses through x = 1/2 or x = 0.5; the x intercept as an ordered pair would be (1/2, 0) or (0.5, 0)

side note: the equation y = 4x-2 goes through the points (0,-2) and (1,2). You find this by plugging in x = 0 and x = 1 respectively to find the corresponding y values.

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3 years ago

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Answer:

The system of equations that models the problem is:

$\left \{ {{2*H+3*C=4.95} \atop {3*H+2*C=5.45}} \right.$

Step-by-step explanation:

A system of equations is a set of two or more equations with several unknowns in which we want to find a common solution. So, a system of linear equations is a set of (linear) equations that have more than one unknown that appear in several of the equations. The equations relate these variables or unknowns to each other.

In this case, the unknown variables are:

H: price of a can of corn beef hash
C: price of a can of creamed chipped beef

Knowing the unit price of a product, the price of a certain quantity of that product is calculated by multiplying that quantity by the unit price. So the price for 2 cans of ground beef hash can be calculated as 2 * H and the price for 3 cans of ground beef with cream can be calculated as 3 * C. Jan paid $ 4.95 for those amounts from both cans. This means that the sum of the can prices must be $ 4.95. So: 2*H + 3*C= 4.95 Equation (A)

Thinking similarly, if Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45, Wayne's buy can be expressed by the equation:

3*H + 2*C= 5.45 Equation (B)

Finally, the system of equations that models the problem is:

$\left \{ {{2*H+3*C=4.95} \atop {3*H+2*C=5.45}} \right.$

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