Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
Answer:
Option (3)
Step-by-step explanation:
By applying cosine rule in the triangle ABC,
BC² = AC² + AB² - 2(AC)(AB)cosA
5² = 3² + 7²- 2(3)(7)cosA
25 = 9 + 49 - 42cos(A)
25 = 58 - 42cos(A)
cos(A) = 
A = 
A = 38.21°
A ≈ 38°
Option (3) will be the correct option.
He ANWSER I got would be c idk if this is right or not I honk it might be
If (y-1) is a factor of f(y), f(y)=0 when y=1. So if you find that f(1)=0, then (y-1) is a factor of f(y).
f(y)=y^3-9y^2+10y+5
f(1)=1-9+10+5=7
Since f(1)=7, (y-1) is not a factor.
Answer:
It is about 537.2
Step-by-step explanation:
V= π · r^2 · h
V= π · 3^2 · 19
V≈ 537.2
