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Dmitry [639]
3 years ago
8

Help me solve this.... ​

Mathematics
1 answer:
rodikova [14]3 years ago
4 0

Answer:

1. Solution,\\Let~x=0.272727......\\Then, 100x = 27.272727.....\\Now,\\100x-x = 27.272727..... - 0.27272727..... = 27.\\or, 99x = 27\\or, x = \frac{27}{99} = \frac{3}{11}\\Thus,~\frac{3}{11} =0.27272727......\\

2. (27)^\frac{2}{3}.(125)^\frac{1}{3}\\= (3^3)^\frac{2}{3}.(5^3)^\frac{1}{3}\\=(3^2)(5)\\=45.

3. Solution,\\Here, \frac{1}{5} = 0.2\\\frac{1}{2} = 0.5\\Now, ~Irrational~ numbers~ between~ 0.2 ~and~ 0.5 ~are~ 0.2122275647.......~and~0.467858930.......\\

You can write any numbers between 0.2 and 0.5 which follow irregular patterns like this.

OR\\Examples~of~such~irrational~numbers~are~5+\sqrt{7}~ and~5-\sqrt{7} .

4. Solution,\\x^2+y^2 = (x+y)^2-2xy=5^2-2(10) = 25-20=5.\\5.~ If~x=-3~and~y=-2~are~the~solutions~of~the~equation~2x-3y=k,~then,\\2(-3)-3(-2)=k\\or, k = -6+6\\or, k = 0

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Tanya [424]

Answer:

C

Step-by-step explanation:

(2x + 3)^5 = C(5,0)2x^5*3^0 +

C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5

Recall that

C(n,r) = n! / (n-r)! r!

C(5,0) = 1

C(5,1) = 5

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C(5,3) = 10

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C(5,5) = 1

= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5

= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243

= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243

= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243

7 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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tresset_1 [31]

Answer:

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Step-by-step explanation:

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