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Flauer [41]
3 years ago
13

Please help mee

Mathematics
1 answer:
Bess [88]3 years ago
5 0

Answer:

$47,616

Step-by-step explanation:

49,600 x .04 = 1984

49,600- 1984 = $47,616

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Assume that there are 365 days in a year, the probability that a person is born on any given day is the same for all days, and e
Artemon [7]

Answer:

Step-by-step explanation:

If each day equal chance then p = Prob that a person is borne on a particular day = 1/365

Each person is independent of the other and there are two outcomes either borne in July or not

p = prob for one person not borne in July = (365-31)/365 = 334/365

a)Hence prob that no one from n people borne in July = (\frac{334}{365} )^n

b) p = prob of any one borne in July or Aug = \frac{(31+31) }{365} =\frac{62}{365}=0.1698

X- no of people borne in July or Aug

n =15

P(X>=2) =15C2 (0.1698)^2*(1-0.1698)^{13} +15C3 (0.1698)^3*(1-0.1698)^{12} +...+15C15 (0.1698)^{15}

=0.7505

3 0
2 years ago
Please help, Thanks.
Evgen [1.6K]

Answer:

C

Step-by-step explanation:

49x² + 28xy + 4y² ← is a perfect square of the form

(ax + by)² = a²x² + 2abxy + b²y²

49 = 7² ⇒ a = 7 and 4 = 2² ⇒ b = 2

2ab = 2 × 7 × 2 = 28

Hence

49x² + 28xy + 4y² = (7x + 2y)²

with factor 7x + 2y ⇒ C

8 0
3 years ago
Does anyone know this need help
madreJ [45]

Answer:

32 m

Step-by-step explanation:

The distance across the river is give as x and we are interested in finding the value of x.

Both the triangles are similar by AA Postulate.

Therefore,

20/x = 10/16 (by c.s.s.t.)

2/x = 1/16

x = 16*2

x = 32 m

8 0
3 years ago
Find the magnitude and direction (in degrees) of the vector. (Assume 0° ≤ < 360°.)
ddd [48]

6i~~ + ~~2\sqrt{3}j\implies < \stackrel{a}{6}~~,~~\stackrel{b}{2\sqrt{3}} > \\\\[-0.35em] ~\dotfill\\\\ \stackrel{magnitude}{\sqrt{a^2+b^2}}\implies \sqrt{6^2+(2\sqrt{3})^2}\implies \sqrt{36+(2^2\cdot 3)}\implies \sqrt{36+12}\implies \sqrt{48} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{direction}{tan^{-1}\left( \cfrac{b}{a}\right)}\implies tan^{-1}\left( \cfrac{2\sqrt{3}}{6} \right)\implies tan^{-1}\left( \cfrac{\sqrt{3}}{3} \right) \\\\\\ tan^{-1}\left( \cfrac{1}{\sqrt{3}} \right)\implies 30^o

3 0
2 years ago
(1CQ) Write the repeating decimal as a fraction .51
egoroff_w [7]

Answer: Your answer is 17/33! Hope this helps. If you need anymore help let me know!

8 0
3 years ago
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