45 - 20 =??? and for the other 1... 1,400 + 7,437 = ???
For 95% CI
x - 0.05s = 100
x + 0.05s = 120
Solve for x and s
The interval for u with 90% is
x - 0.10s
and
x + 0.10s
Substitute x and s
Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
I'm sorry no one can answer and where is the question?
Please put in the question and I might be able to help!
Answer:
D.1440
Step-by-step explanation:
V=lxwxh
10x12x12
1440
