Hello!
The Correct Answer to this would be 100%:
Option "85.4".
(Work Below)
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
<span>11.333 m = radius
</span>
the area beneath an arc:
Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ).
</span>
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²
Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]
Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]
Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m
Area = 138.828 m² - 53.333 m²
Area = 85.4 m<span>²
</span>
Hope this Helps! Have A Wonderful Day! :)
And as Always...
The Correct Answer to this would be 100%:
Option "85.4".
(Work Below)
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
<span>11.333 m = radius
</span>
the area beneath an arc:
Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ).
</span>
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²
Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]
Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]
Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m
Area = 138.828 m² - 53.333 m²
Area = 85.4 m<span>²
</span>
Hope this Helps! Have A Wonderful Day! :)
And as Always...