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3 years ago

The product of eight and a number x

Mathematics

1 answer:

Julli [10]3 years ago

8 0

Answer:

To write this down as an algebraic expression you would simply need to multiply the two terms together.

So in this case it would be 8 multiples by x which is 8x

Step-by-step explanation:

1) Find out the variables in the Expression

2) Find the operation that is done to the variables

3) Apply the operation to those variables.

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9 2/3 – 4 1/5?<br> I don’t really know and umm yea …

11Alexandr11 [23.1K]

The Exact form would be 82/15
The decimal form would be 5.46
The mixed number form would be 5 7/15

5 0

2 years ago

Read 2 more answers

PLEASE HELP!! DUE SOON

mrs_skeptik [129]

Answer:

b=3a/8

a=8b/3

Step-by-step explanation:

b/a=k ( k is the constant proportional)

3/8=9/24=15/40

b/a=3/8

b=3a/8

a=8b/3

I hope this is right answer

7 0

2 years ago

Pls I’m about to cry...

marissa [1.9K]

FORMULA:

Volume of cylinder = πr²h
Volume of sphere = 4/3πr³

ANSWER:

Volume of capsule = 4/3πr³ + πr²h

πr²(4/3r + h)

3.14 × 2²(8/3 + 5.6)
3.14 × 4(2.6 + 5.6)
12.56(8.2)
102.99 or 103 rounded.

Now, Density = 0.7mg/mm³

0.7/103
0.00679mg

7 0

2 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

Can u plz help me in this plz?

Yanka [14]

There isn’t a picture what do you need help with

7 0

2 years ago