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dusya [7]
3 years ago
7

What is the slope of the line that passes through the points (-2, 4) and (1, 4)?

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

there is no slope. y = 4, the line is horizontal

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Find the range of the data.<br> 73, 69, 78, 68, 70, 86, 80, 72<br> The range is
Fiesta28 [93]
The answer is 18.

Work:
[i]The range is the gap between the smallest value and the largest value. [/i]

The smallest is 68.
The largest is 86.
The gap between them is 86-68=18.
5 0
3 years ago
Read 2 more answers
−4(3m−3)+(−10+8m)=?
Valentin [98]
-4(3m-3)+(-10+8m)
12m+12-1+8m
12m+8m = 20m
+12 -1= +11
answer: 20m+11


*note negative times a negative equals positive and negative times positive is negative 
first: you multiply -4 by 3m which is -12m.
second: you multiply -4 by -3 which is +12
third: find the invisible which is 1. (located right here: +(1) (-10+8m)
fourth: multiply invisible 1 by -10 which is -10
fifth: multiply invisible one by +8m which is +8m 
sixth: combine like terms
seventh: answer
 
5 0
3 years ago
A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square?
AlexFokin [52]
The area of a square would me multiplying the width times the length and then multiplying by one half would be like splitting the square in half so your answer would be that last one right there. 6*6= area then multiply by 1/2 = half of area  Hope this helps! :D 
6 0
3 years ago
Graph f(x)=2x and g(x)=2^x on the same coordinate plane. What is the solution to the equation f(x)=g(x) ? Enter your answer in t
Serjik [45]

Answer:

(1,2)\:\:and\:\:(2,4)

Step-by-step explanation:

The graph of the two functions are shown on the same diagram in the attachment above;

The solution to the equation f(x)=g(x) is where the two graphs intersected.

These points are

(1,2)\:\:and\:\:(2,4)

8 0
3 years ago
Read 2 more answers
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
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