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exis [7]
2 years ago
7

Find f(a-2) when f(x)= 2x^2 +3x

Mathematics
1 answer:
Zarrin [17]2 years ago
4 0
Hopefully this helps

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1. Renting a bicycle at a local Bike shop costs $30 for the first day and $10 for each additional day.
r-ruslan [8.4K]
(a)    d=days C=cost  
   
       d       C
       1       30
       2       40
       3       50
       4       60

C=10(d-1)+30

(b) C=10(5-1)+30
      C=40+30
      C=70
7 0
3 years ago
Arrow 1 is rotated by 45° , 90° , 180° respectively as shown below , Based on this we can say – “Any object when rotated by ____
Free_Kalibri [48]

Any object when rotated by 360°, will look exactly the same

7 0
2 years ago
Use Green's Theorem to calculate the circulation of F =2xyi around the rectangle 0≤x≤8, 0≤y≤3, oriented counterclockwise.
Tamiku [17]

Green's theorem says the circulation of \vec F along the rectangle's border C is equal to the integral of the curl of \vec F over the rectangle's interior D.

Given \vec F(x,y)=2xy\,\vec\imath, its curl is the determinant

\det\begin{bmatrix}\frac\partial{\partial x}&\frac\partial{\partial y}\\2xy&0\end{bmatrix}=\dfrac{\partial(0)}{\partial x}-\dfrac{\partial(2xy)}{\partial y}=-2x

So we have

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D-2x\,\mathrm dx\,\mathrm dy=-2\int_0^3\int_0^8x\,\mathrm dx\,\mathrm dy=\boxed{-192}

6 0
3 years ago
PLZ SOLVE PIC ATTACHED BELOW
ludmilkaskok [199]

Answer:

\tan(51°)  =  \frac{10}{x}  \\x =  \frac{10}{ \tan(51°) }  \\ x = \frac{10}{1.235}  \\ \boxed{ x = 8.1}

<h3>★ Value of x is <u>8.1</u>.</h3>

\sin(51°)=  \frac{10}{H}  \\ h =  \frac{10}{ \sin(51°) }  \\ H=  \frac{10}{0.777}  \\  \boxed{H= 12.8676}

<h3>★ Value of H is <u>12.8676</u>.</h3>

Remember:

  • tan∅=Perpendicular/Base
  • sin∅=Perpendicular/Hypotenuse

4 0
2 years ago
Can you guys help me out pls
kozerog [31]
Answer is for sure b
8 0
2 years ago
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