Responder:
<h3>45.49 unidades
</h3>
Explicación paso a paso:
La pregunta está incompleta. La pregunta puede reestructurarse así;
María va en bicicleta, por un camino completamente llano, pero inclinado; encuentra los 2 puntos de referencia de dicho camino y son D = (20; 32), E = (45; 70), encuentra la distancia recorrida por María.
La distancia total cubierta por María se puede obtener tomando la distancia entre los dos puntos de referencia usando la fórmula;
D = √ (x₂-x₁) ² + (y₂-y₁) ²
Dadas las coordenadas D = (20; 32), E = (45; 70),
DE = √ (45-20) ² + (70-32) ²
DE = √ (25) ² + (38) ²
DE = √625 + 1444
DE = √2069
DE = 45,49
Por lo tanto, la distancia total recorrida por María es de 45,49 unidades.
Answer:
5/7
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
a)
The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.
To calculate the mean for data organized in this type of table you have to use the following formula:
X[bar]= (∑x'fi)/n
Where
x' represents the class mark of each class interval and is calculated as (Upper bond + Lower bond)/2
fi represents the observed frequency for each class
n is the total of observations, you can calculate it as ∑fi
<u>Class marks:</u>
x₁'= (120+124)/2= 122
x₂'= (124+128)/2= 126
x₃'= (128+132)/2= 130
x₄'= (132+136)/2= 134
x₅'= (136+140)/2= 138
Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.
n= 7 + 8 + 13 + 9 + 3= 40
X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3
The estimated average height is 129.3cm
b)
This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.
The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a mean value within the interval to calculate the mean of the sample.
I hope this helps!
The value of four is not greater than five of corse if the value of four were positive and five negative but four is not greater the five.
It would take 7:30 minutes to clear the rest of the 10 miles.
