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4 years ago

Can someone solve number 32?

Mathematics

1 answer:

MaRussiya [10]4 years ago

8 0

This one above lol ,......................m

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1. What is the theoretical probability that a coin toss results in 20 showing?

salantis [7]

Ummm i dont even believe thats a reasonable question theres no 20 cent coins

6 0

3 years ago

Find the value of c so that (x-5) is a factor of the polynomial p(x)

liubo4ka [24]

I think the question is

Find the value of c so that (x-5) is a factor of the polynomial

$p(x) = x^3 + 2x^2 + cx + 10$

The other factor is going to be some quadratic. We can say a few things about its coefficients but let's start by saying in general it's

$q(x)= ax^2 + bx + k$

$p(x) = (x-5)q(x)$

$x^3 + 2x^2 + cx + 10 = (x-5)(ax^2 + bx+k) = ax^3 + (b-5a)x^2 + (k-5b)x - 5k$

Equating respective coefficients,

$a=1$

$b-5a = 2$

$k - 5b = c$

$-5k = 10$

so we get

$b = 2 + 5 = 7$

$k = 10/-5 = -2$

$c = k - 5b = 2 - 5(7)= -37$

Answer: -37

Check:

$(x^2 + 7x - 2)(x - 5) = x^3 + 2 x^2 - 37 x + 10\quad\checkmark$

7 0

3 years ago

a dog food company sells its canned dog food to stores for $0.35 per can. one of the stores sells the can of dog food for $0.79.

iris [78.8K]

To answer your question its 27.65

6 0

3 years ago

A hair salon receives a shipment of 84 bottles of hair conditioner to use and sell to customers. The two types are labels type A

Rom4ik [11]

$x-\ botlle\ A\\y-\ bottle\ B\\\\ \left \{ {{x+y=84} \atop {6,5x+8,25y=588}} \right. \\\\ \left \{ {{x=84-y} \atop {6,5x+8,25y=588}} \right. \\\\Substitution\ method\\\\
6,5(84-y)+8,25y=588\\\\
546-6,5y+8,25y=588\ \ \ | subtract\ 546
1,75y=42\ \ \| divide\ by\ 1,75\\\\y=24\\\\There\ were\ 24\ bottles\ B\ and\ 42\ bottle\ A.$

6 0

3 years ago

A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H

andrey2020 [161]

Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}$

solve for "x"

what's "y"? well, y = 100 - x

4 0

3 years ago