Can someone solve number 32?
1 answer:
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Answer:
<em>First term of the given series = 4</em>
<em>The last term of the given series = 11</em>
Step-by-step explanation:
<u><em>Explanation</em></u>
<em>Given that the sum of the series</em>
<em> ∑⁸ₙ₋₁ (n+3)</em>
The term of the given sequence
aₙ = (n+3)
Put n=1
a₁ = 1+3 = 4
Put n=2
a₂ = 2+3 =5
Put n=3
a₃ = 3+3 = 6
Put n=4
a₄ = 4+3 =7
Put n=5
a₅ = 5+3 =8
Put n=6
a₆ = 6+3 =9
Put n=7
a₇ = 7+3 = 10
Put n=8
a₈ = 8+3 =11
The sequence of the given series
4,5,6,7,8,9,10,11
<u><em>Final answer:-</em></u>
<em>First term of the given series = 4</em>
<em>The last term of the given series = 11</em>
<em> </em>