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nadya68 [22]
4 years ago
6

Can someone solve number 32?

Mathematics
1 answer:
MaRussiya [10]4 years ago
8 0
This one above lol ,......................m

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In one week 215,328 people visit the Grand Canyon how many hundreds of people visit the Grand Canyon that week
Firdavs [7]
2 because it's 200,000 so two hundreds of people
8 0
3 years ago
(8w)^2 without parentheses
Nataly [62]

Answer:

I believe the answer would be 64w2.

Step-by-step explanation:

8 squared is 8 x 8, which equals 64, and then w squared is just w2, since we don't know what it is. Put them together, and the answer is 64w2.

5 0
4 years ago
• A car uses 30 gallons of gasoline for a trip of 800 miles. How many gallons would
nevsk [136]

Quantity of gasoline needed by a car to run 800 miles = 30 gallons

Quantity of gasoline needed by a car to run 1 mile =

= 30 ÷ 800

= 0.0375 gallons

So , to run 1 mile a car would need = 0.0375 gallons of oil

To run 700 miles the quantity of gasoline needed =

= 700 × 0.0375

= 26.25 gallons of gasoline

Therefore , a car will use 26.25 gallons of gasoline on a trip of 700 miles .

7 0
4 years ago
What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2
Alex73 [517]

Answer:

d=1

Step-by-step explanation:

\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4} =\frac{-2}{d+2}

Now make the denominators same

LCD: (d-4)(d+2)

\frac{-3d}{(d-4)(d+2)} +\frac{3(d+2)}{(d-4)(d+2)} =\frac{-2(d-4)}{(d+2)(d-4)}

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1




3 0
3 years ago
Read 2 more answers
Find the constant rate of change for each linear function and interpret its meaning
Marina CMI [18]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

and to get it, we simply need two points off of the straight line, hmm let's use the ones in the picture below.

(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

3 0
2 years ago
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