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Kisachek [45]
3 years ago
8

1.

Mathematics
1 answer:
Margarita [4]3 years ago
5 0

Answer:

The ball throw into the air with an initial velocity of 22 meters per second is 27.4 meters above the ground after 3 seconds.

Step-by-step explanation:

The quadratic function h(t) = -4.9t^2 + 22t + 5.5 represents the height of the ball above the ground, h(t), in meters, with respect to time, t, in seconds.

To find h(3), substitute t = 3 into the function expression:

h(3)=-4.9\cdot 3^2+22\cdot 3+5.5\\ \\=-4.9\cdot 9+66+5.5\\ \\=-44.1+71.5\\ \\=27.4

Meaning: the ball throw into the air with an initial velocity of 22 meters per second is 27.4 meters above the ground after 3 seconds.

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