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Kisachek [45]
3 years ago
8

1.

Mathematics
1 answer:
Margarita [4]3 years ago
5 0

Answer:

The ball throw into the air with an initial velocity of 22 meters per second is 27.4 meters above the ground after 3 seconds.

Step-by-step explanation:

The quadratic function h(t) = -4.9t^2 + 22t + 5.5 represents the height of the ball above the ground, h(t), in meters, with respect to time, t, in seconds.

To find h(3), substitute t = 3 into the function expression:

h(3)=-4.9\cdot 3^2+22\cdot 3+5.5\\ \\=-4.9\cdot 9+66+5.5\\ \\=-44.1+71.5\\ \\=27.4

Meaning: the ball throw into the air with an initial velocity of 22 meters per second is 27.4 meters above the ground after 3 seconds.

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I NEED HELP BEING TIMED
Paladinen [302]

Answer:

18

Step-by-step explanation:

there are 4 cups in a quart. 4*5 1/2=22

22-4=18

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4 0
3 years ago
What is the value of c? 13c−22=−17c+14
elena-s [515]
13c-22=-17c+14
-14 -14
13c-36=17c
-13 -13
-36\4=4\42
C=-9
3 0
3 years ago
Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend. How many gallons of ice tea does Morris have left?
lara31 [8.8K]

Answer:

2 \frac{9}{28} gallons of ice tea is left with Morris

Step-by-step explanation:

Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend.

Morris has 2 3/4 gallons of ice tea

2\frac{3}{4}= \frac{2*4+3}{4}=\frac{11}{4}

He gives 3/7 of it to her friend.

To find how many gallons of ice tea does Morris have left , we subtract 3/7 from 11/4

\frac{11}{4}- \frac{3}{7}

Make the denominators same

\frac{11*7}{4*7}- \frac{3*4}{7*4}

\frac{77}{28}- \frac{12}{28}

\frac{65}{28}

\frac{65}{28} = 2 \frac{9}{28}

7 0
3 years ago
Which equation can be used to solve for the rate, r, for Sam to change all the light bulbs in the office building by himself?
Bad White [126]

Answer:

\frac{3}{r}+\frac{3}{8}=1

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Working together, Sam and Charlie can change all light bulbs in the office building in 3 hours. It would have taken Charlie 8 hours to do the job alone. Which equation can be be used to solve for the rate 'r', for Sam to change all the light bulbs in the office building by himself.

Let Sam can change the bulbs in the office alone in 'r' hours  

Per hour work done by Sam alone = \frac{1}{r}

Let Sam takes he time to change the same bulbs in the office alone = 8 hours

Per hour work done by Sam = \frac{1}{8}

Since, Sam and Charlie complete the work together in time = 3 hours

Therefore, per hour work done by both = \frac{1}{3}

Equation for per work done by both will be,

Per hour work done by both = Per hour  work done by Sam alone + Per hour work done by Charlie

\frac{1}{r}+\frac{1}{8}=\frac{1}{3}

Therefore, equation for the rate 'r' will be,

\frac{1}{r}+\frac{1}{8}=\frac{1}{3}

\frac{3}{r}+\frac{3}{8}=1

8 0
3 years ago
Read 2 more answers
A researcher wants to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual
atroni [7]

Complete question is;

A researcher wants to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual containers are randomly assigned to two different groups. Plants in both groups are treated identically, except that the plants in group 1 are sprayed weekly with a kelp extract, while the plants in group 2 are not. After the first frost, 12 of the 50 plants in group 1 exhibited damage and 18 of the 50 plants in group 2 showed damage. Let p1 be the actual proportion of all tomato plants of this variety that would experience damage under the kelp treatment, and let p2 be the actual proportion of all tomato plants of this variety that would experience damage under the no-kelp treatment. Is there evidence of a decrease in the proportion of

tomatoes suffering frost damage for tomatoes sprayed with kelp extract? To determine

this, yo u test the hypotheses H0: p1 = p2, Ha: p1 < p2. The p - value of your test is

A) greater than 0.10.

B) between 0.05 and 0.10.

C) between 0.01 and 0.05.

D)between 0.001 and 0.01.

E) below 0.001.

Answer:

B) between 0.05 and 0.10.

Step-by-step explanation:

We are given;

Number of plants in group that exhibited damage = 12

Number of group 1 plants; n₁ = 50

Number of plants in group 2 that exhibited damage = 18

Number of group 2 plants; n₂ = 50

Proportion of plants in group 1 that exhibited damage; p₁^ = 12/50 = 0.24

Proportion of plants in group 2 that exhibited damage; p₂^ = 18/50 = 0.36

Pooled proportion; p¯ = (12 + 18)/(50 + 50) = 0.3

q¯ = 1 - p¯

q¯ = 1 - 0.3 = 0.7

Z-score will be;

z = ((p₁^ - p₂^) - 0)/√((p¯•q¯)×((1/n₁) + (1/n₂))

Plugging in the relevant values;

z = (0.24 - 0.36)/√((0.3 × 0.7) × ((1/50) + (1/50))

z = -0.12/0.092

z = -1.3

From z-distribution table attached, we have;

p-value = 0.0968

Correct answer is option B.

8 0
2 years ago
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