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tresset_1 [31]
3 years ago
13

What percent of 45 is 135? Explain your reasoning.

Mathematics
2 answers:
MrRissso [65]3 years ago
6 0
The question is equal to: 135 / 45

Divide:

135 / 45 = 3

3 = 300%

Answer = 300% (I think)

~Hope this helped~


jek_recluse [69]3 years ago
6 0
29.6296296296 is the correct answer. All you do is 45 divided by 135 times 100
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Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi
Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ;  2Bs and 3Cs it is possible to get a palindrome if you fixed the  letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

<u>C</u> (       ) <u>C</u> (       ) <u>C</u>

To fill in the gaps we have  4 letters  A and 2 letters B, wich we have two divide in two palindrome gaps,  

AAB         and    BAA the palindrome is  C  AAB C BAA C

BAA         and    AAB    "           "           is  C  BAA C AAB C  

ABA         and    ABA    "           "           is  C  ABA C ABA C

b) 4 A  ;   2B  ; 3C

We have the total number of elements  9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A  ; 2 B  ; 2C  : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

5 0
3 years ago
Been trying this for too long thanks
11Alexandr11 [23.1K]

Answer:

It's 1.6 and 0.8

Step-by-step explanation:

7 0
3 years ago
8/2(2+2)=<br><br> A. 16<br> B. 1<br> C. 0<br> D. 10
s2008m [1.1K]

The answer to this problem is 16.

To solve we must follow the order of operations.

8/2 is 4.

2+2 is 4.

So, now we multiply 4(4) and will get 16 as the answer

So, 16 is the answer.

4 0
3 years ago
-6/7 x (-5/4)<br><br> Pls put it as a fraction :)
antiseptic1488 [7]

Answer:

15/14

Step-by-step explanation:

I put it into the scientific desmos calculator online

7 0
3 years ago
Read 2 more answers
I really need an a answer again Srry for wasting ur time... but I need an answer quick
defon

Answer:

400m

7000000km

25000m

Step-by-step explanation:

Meter to Kilometer is x1000

kilometer to meter is ÷1000

5 0
3 years ago
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