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3 years ago

15

Find the area of a composite shape below:

1 answer:

yuradex [85]3 years ago

7 0

Answer:

To find the area of a composite figure, separate the figure into simpler shapes whose area can be found. Then add the areas together. Be sure than none of the simpler figures have overlapping areas. Example 1: Find the area of the composite shape shown below.

Step-by-step explanation:

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Determine whether the geometric series 19.2 + 9.6 + 4.8 + ... converges or diverges, and identify the sum if it exists.

zloy xaker [14]

Answer: The infinite geometric series converges to 38.4

====================================================

Explanation:

Divide each term by its previous term

term2/term1 = 9.6/19.2 = 0.5

term3/term2 = 4.8/9.6 = 0.5

The common ratio is r = 0.5

Since -1 < r < 1 is true, this means the infinite geometric series converges.

It converges to...

S = a/(1-r)

S = 19.2/(1-0.5)

S = 38.4

6 0

3 years ago

What is 372777177771136661331x132747717743716662141284957x0=

lubasha [3.4K]

Answer:

0

Step-by-step explanation:

Anything times zero, is zero.

7 0

2 years ago

PLEASE HELP ME FOR BRAINLIEST Reduce to simplest form. 6/3+(-1/6)

Leni [432]

Answer: 1 5/6, or 11/6, or 1.83333333

Step-by-step explanation:

$\frac{6}{3} + -\frac{1}{6}$

6/3 is 2.

Thus, the answer is 2 - 1/6 or 1 5/6

7 0

3 years ago

Read 2 more answers

A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc

aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

$AC^{2} =AB^{2} +BC^{2}$

Substituting the values of BC = 3 and AC = 5, we have,

$5^{2} =AB^{2} +3^{2}$

Squaring the terms, we get,

$25 =AB^{2} +9$

Subtracting both sides by 9, we have,

$16 =AB^{2}$

Taking square root on both sides,

$AB = 4$

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0

3 years ago

Please help me with this!!

Dennis_Churaev [7]

angle QRP=180-(64+47)

=69°

Using sin rule,

p/sinP=q/sinQ.

7.6/sin64=q/sin47

q=6.2cm

Using the formula;

area=1/2p*qsinR

we have;

1/2×7.6×6.2×sin69°=21.995

answer= 22

7 0

3 years ago