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3 years ago

Triangle ABC is shown below.

Mathematics

1 answer:

inna [77]3 years ago

3 0

Answer:

the answer is 14 C

Step-by-step explanation:

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Find the area of the region bounded by the curves y equals the inverse sine of x/4, y = 0, and x = 4 obtained by integrating wit

olasank [31]

Answer: 1/30

Step-by-step explanation:

∫[0,4] arcsin(x/4) dx = 2π-4

x = 4sin(u)

arcsin(x/4) = arcsin(sin(u)) = u

dx = 4cos(u) du

∫[0,4] 4u cos(u) du

∫[0,4] f(x) dx = ∫[0,π/2] g(u) du

v = ∫[1,e] π(R^2-r^2) dx

where R=2 and r=lnx+1

v = ∫[1,e] π(4-(lnx + 1)^2) dx

Using shells dy

v = ∫[0,1] 2πrh dy

where r = y+1 and h=x-1=e^y-1

v = ∫[0,1] 2π(y+1)(e^y-1) dy

v = ∫[0,1] (x-x^2)^2 dx = 1/30

3 0

3 years ago

Will give brainliest, please help fast

Gekata [30.6K]

Answer:

Converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

Step-by-step explanation:

we are given quadratic equation: $x^2-20x+13=0$

And we need to convert it into completing the square method.

Completing the square method is of form: $a^2-2ab+b^2=(a-b)^2$

Looking at the given equation $x^2-20x+13=0$

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as: 2(x)(10)

So, we need to add and subtract (10)^2 on both sides

$x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87$

So, converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

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3 years ago

Which of the following equations represents a parabola that reaches its minimum value at (- 2, - 3)?

nlexa [21]

Yay me following equations

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3 years ago

consider the point (x,y) lying on the graph of y=(x+3)^1/2. let L be the distance between the points (x,y) and (4,0). write l as

olga_2 [115]

$L=\sqrt{ (x-4)^2 + y^2 }$
and
$y=\sqrt{x+3} \Rightarrow x = y^2-3$

$L=\sqrt{ (x-4)^2 + y^2 }=\sqrt{ (y^2 - 3-4)^2 + y^2 }=\sqrt{ (y^2-7)^2 + y^2 }$

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3 years ago

What is the measure of XYZ shown in the diagram below?

Crazy boy [7]

Answer: A.

Explenation: Apex

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4 years ago

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